iOS Facebook 分享

在获得grantedPermissions“publish_actions”之后，现在我希望用户希望用户在不离开当前 View 的情况下将消息和图像(本地生成)发送到他们的Facebook时间线。

我试过FBSDKShareAPI接口(interface)，但这不是我想要的效果。我希望用一个消息和一个图像来实现一个状态。我该怎么办？

FBSDKSharePhoto* photo = [[FBSDKSharePhoto alloc]init];
photo.image = self.shareImage;
photo.userGenerated = YES;

FBSDKSharePhotoContent * content = [[FBSDKSharePhotoContent alloc]init];
content.photos = @[photo];

if ([[FBSDKAccessToken currentAccessToken].permissions containsObject"publish_actions"]) {
    FBSDKShareAPI * shareApi = [[FBSDKShareAPI alloc]init];
    shareApi.message = self.tf.text;
    [shareApi createOpenGraphObjectbject];
    [FBSDKShareAPI shareWithContent:content delegate:self];
    [shareApi share];
  }

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Best Answer-推荐答案

您分享了两次相同的内容，这可能是您无法通过一张图片(而是获得两张)获得一条状态消息的原因:

[FBSDKShareAPI shareWithContent:content delegate:self];
[shareApi share];

您可能不需要为此创建一个开放的图形对象。试试这个:

NSURL *imageURL = [NSURL URLWithString"https://upload.wikimedia.org/wikipedia/en/d/d3/Nasa_mer_marvin.jpg"];
UIImage *image = [UIImage imageWithData:[NSData dataWithContentsOfURL:imageURL]]; // taking image from Wikipedia for example purposes
FBSDKSharePhoto *photo = [[FBSDKSharePhoto alloc] init];
photo.image = image; // photo.image = self.shareImage;
photo.userGenerated = YES;
FBSDKSharePhotoContent *content = [[FBSDKSharePhotoContent alloc] init];
content.photos = @[photo];
if ([[FBSDKAccessToken currentAccessToken].permissions containsObject"publish_actions"]) {
    FBSDKShareAPI * shareApi = [[FBSDKShareAPI alloc]init];
    shareApi.message = @"Lorem Ipsum Dolor Sit Amet"; // shareApi.message = self.tf.text;
    shareApi.shareContent = content;
    [shareApi share];
}

关于iOS Facebook 分享，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/31313416/