Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
235 views
in Technique[技术] by (71.8m points)

c++ - Why doesn't explicit bool() conversion happen in contextual conversion

If the following test-programm

#include <iostream>

class A {
public:
    A() {}
    explicit operator bool() const {
        std::cout << __PRETTY_FUNCTION__ << std::endl;
        return true;
    }
//    explicit operator bool() {
//        std::cout << __PRETTY_FUNCTION__ << std::endl;
//        return true;
//    }
    const operator int() const {
        std::cout << __PRETTY_FUNCTION__ << std::endl;
        return 1;
    }
    operator int() {
        std::cout << __PRETTY_FUNCTION__ << std::endl;
        return 1;
    }
};

int main() {
    A a;
    if (a) {
        std::cout << "bool()" << std::endl;
    }
    if (a + 0) {
        std::cout << "int()" << std::endl;
    }
}

is run, the output is

int A::operator int()
bool()
int A::operator int()
int()

and not

bool A::operator _Bool()
bool()
int A::operator int()
int()

what I expected (and what you get if you uncomment the commented parts).

So the question is what are the rules giving the conversion to non-const-int precedence over converting to const-bool?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

When performing overload resolution on a reference binding, the less cv-qualified type is preferred. This is discussed in 13.3.3.2p3, with the example given:

struct X {
  void f() const;
  void f();
};
void g(const X& a, X b) {
  a.f(); // calls X::f() const
  b.f(); // calls X::f()
}

Note that binding an object to the implicit object parameter of a member function (13.3.1.1.1p2) is a reference binding (13.3.3.1.4).

Conversion operators are treated as member functions (13.3.1.5) for the purposes of overload resolution (13.3p2). Contextual conversion to bool has the semantics of initialization (4p4).

Importantly, any conversion required on the return type of the conversion operator is considered only after considering overload resolution between the conversion operators themselves (13.3.3p1).

The solution is to ensure that all conversion operators have the same const-qualification, especially to scalar type.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...