c - Call menu function in another function

Question

I'm trying to call menu function in the main function and let it prompt until the user decides to quit, but seems like it's not giving me response.. I'm new at this website coding, let me know if there's anything eg. post format I can improve!

clearkeyboard function:

void clearKeyboard(void)
{
    int c;
    while ((c = getchar()) != '
' && c != EOF);
}

The function to call menu:

void ContactManagerSystem(void)
{
    int contactchoice;
    int done = 1;
    char yesno, c;
    do {
        clearKeyboard();
        contactchoice = menu();
        switch (contactchoice) {
        case 1:
            printf("<<< Feature 1 is unavailable >>>
");
            break;
        case 2:
            printf("<<< Feature 2 is unavailable >>>
");
            break;
        case 3:
            printf("<<< Feature 3 is unavailable >>>
");
            break;
        case 4:
            printf("<<< Feature 4 is unavailable >>>
");
            break;
        case 5:
            printf("<<< Feature 5 is unavailable >>>
");
            break;
        case 6:
            printf("<<< Feature 6 is unavailable >>>
");
            break;
        case 0:
            printf("Exit the program? (Y)es/(N)o: ");
            scanf("%c%c", &yesno, &c);
            if (yesno == 'Y' || yesno == 'y' && c == '
') {
                done = 0;
                break;
            }
            else if (yesno == 'N' || yesno == 'n')
                break;
        default:
            break;
        }

    } while (done == 1);
}

Menu function:

int menu(void)
{
    int done = 1;
    int choice;
    char c;
    do {
        printf("Contact Management System
");
        printf("-------------------------
");
        printf("1. Display contacts
");
        printf("2. Add a contact
");
        printf("3. Update a contact
");
        printf("4. Delete a contact
");
        printf("5. Search contacts by cell phone number
");
        printf("6. Sort contacts by cell phone numbe
");
        printf("0. Exit

");
        printf("Select an option:> ");
        int rtn = scanf("%d%c", &choice, &c);

        if (rtn == EOF || rtn == 0 || c != '
')
            clearKeyboard();
        else if (choice >= 0 && choice <= 6 && c == '
')
            done = 0;
        else {
            clearKeyboard();
            printf("*** OUT OF RANGE *** <Enter a number between 0 and 6>: ");
            scanf("%d", &choice);
        }
    } while (done == 1);

    return choice;
}

Attached image below is where goes wrong, the correct version should do case 1 instead of keep prompt menu again.

Incorrect Part

Thanks in advance!!!

Answer 1

there are two problem in your code.

1. menu() function returns int and you are matching int with char in switch case case '1': it should be case 1:

2. replace below line

scanf("%c%c", &yesno,&c); with scanf("%c%c", &c,&yesno);

hope this help you.