I have an outer and inner loop, each iterating over a range. I want to exit the outer loop when a condition is satisfied inside the inner loop.
I have a solution which works using two 'break's, one inside the inner loop and one inside the outerloop, just outside the inner loop (a very simplified case for demonstration):
package main
import (
"fmt"
)
func main() {
word := ""
for _, i := range("ABCDE") {
for _,j := range("ABCDE") {
word = string(i) + string(j)
fmt.Println(word)
if word == "DC" {
break
}
}
if word == "DC" {
break
}
}
// More logic here that needs to be executed
}
Go Playground
There is no problem with this solution, but it just looks patched and ugly to me. Is there a better way to do this?
I can try and have another for conditional loop outside the outer loop in the previous solution and have a label and use continue with the label. But as you can see, this approach isn't any more elegant than the solution with break.
package main
import (
"fmt"
)
func main() {
word := ""
Exit:
for word != "DC" {
for _, i := range "ABCDE" {
for _, j := range "ABCDE" {
word = string(i) + string(j)
fmt.Println(word)
if word == "DC" {
continue Exit
}
}
}
}
// More logic here that needs to be executed
}
Go Playground
I have seen similar questions here pertaining to other languages (C, C#, Python etc). But what I am really interested to see is whether there is any trick with Go constructs such as 'for select'.
question from:
https://stackoverflow.com/questions/51996175/how-to-break-out-of-nested-loops-in-go 与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…