Question

How to get address of a pointer in c/c++?

Eg: I have below code.

int a =10;
int *p = &a;

So how do I get address of pointer p? Now I want to print address of p, what should I do?

print("%s",???) what I pass to ???.

question from:https://stackoverflow.com/questions/22250067/how-to-get-address-of-a-pointer-in-c-c

Answer 1

To get the address of p do:

int **pp = &p;

and you can go on:

int ***ppp = &pp;
int ****pppp = &ppp;
...

or, only in C++11, you can do:

auto pp = std::addressof(p);

To print the address in C, most compilers support %p, so you can simply do:

printf("addr: %p", pp);

otherwise you need to cast it (assuming a 32 bit platform)

printf("addr: 0x%u", (unsigned)pp);

In C++ you can do:

cout << "addr: " << pp;