for /r %%v in (*.xls) do ssconvert "%%v" "%%vx"
a couple have people have asked me to explain this, so:
Part 1: for /r %%v in (*.xls)
This part returns an array of files in the current directory that have the xls
extension. The %%
may look a little curious. This is basically the special %
character from command line as used in %PATH% or %TEMP%. To use it in a batch file we need to escape it like so: %%PATH%%
or %%TEMP%%
. In this case we are simply escaping the temporary variable v
, which will hold our array of filenames.
We are using the /r
switch to search for files recursively, so any matching files in child folders will also be located.
Part 2: do ssconvert "%%v" "%%vx"
This second part is what will get executed once per matching filename, so if the following files were present in the current folder:
c:empmySheet.xls,
c:empmySheet_yesterday.xls,
c:empmySheet_20160902.xls
the following commands would be executed:
ssconvert "c:empmySheet.xls" "c:empmySheet.xlsx"
ssconvert "c:empmySheet_yesterday.xls" "c:empmySheet_yesterday.xlsx"
ssconvert "c:empmySheet_20160902.xls" "c:empmySheet_20160902.xlsx"
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