With new_list = my_list
, you don't actually have two lists. The assignment just copies the reference to the list, not the actual list, so both new_list
and my_list
refer to the same list after the assignment.
To actually copy the list, you have various possibilities:
You can use the builtin list.copy()
method (available since Python 3.3):
new_list = old_list.copy()
You can slice it:
new_list = old_list[:]
Alex Martelli's opinion (at least back in 2007) about this is, that it is a weird syntax and it does not make sense to use it ever. ;) (In his opinion, the next one is more readable).
You can use the built in list()
function:
new_list = list(old_list)
You can use generic copy.copy()
:
import copy
new_list = copy.copy(old_list)
This is a little slower than list()
because it has to find out the datatype of old_list
first.
If the list contains objects and you want to copy them as well, use generic copy.deepcopy()
:
import copy
new_list = copy.deepcopy(old_list)
Obviously the slowest and most memory-needing method, but sometimes unavoidable.
Example:
import copy
class Foo(object):
def __init__(self, val):
self.val = val
def __repr__(self):
return 'Foo({!r})'.format(self.val)
foo = Foo(1)
a = ['foo', foo]
b = a.copy()
c = a[:]
d = list(a)
e = copy.copy(a)
f = copy.deepcopy(a)
# edit orignal list and instance
a.append('baz')
foo.val = 5
print('original: %r
list.copy(): %r
slice: %r
list(): %r
copy: %r
deepcopy: %r'
% (a, b, c, d, e, f))
Result:
original: ['foo', Foo(5), 'baz']
list.copy(): ['foo', Foo(5)]
slice: ['foo', Foo(5)]
list(): ['foo', Foo(5)]
copy: ['foo', Foo(5)]
deepcopy: ['foo', Foo(1)]
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