C# XmlNode.ChildNodes breakline count as node

Question

I have these xml

<?xml version="1.0" encoding="UTF-8"?>
<atom:entry xmlns:atom="http://www.w3.org/2005/Atom" xmlns:cmis="http://docs.oasis-open.org/ns/cmis/core/200908/" xmlns:cmisra="http://docs.oasis-open.org/ns/cmis/restatom/200908/">
    <atom:id>urn:uuid:00000000-0000-0000-0000-00000000000</atom:id>
    <atom:title>RenamedDocument</atom:title>
    <atom:updated>2012-07-13T06:14:05Z</atom:updated>
    <cmisra:object xmlns:ns3="http://docs.oasis-open.org/ns/cmis/messaging/200908/">
        <cmis:properties>
        <cmis:propertyString propertyDefinitionId="cmis:name">
                <cmis:value>RenamedDocument</cmis:value>
            </cmis:propertyString>
            <cmis:propertyString propertyDefinitionId="cmisma:[OSTERONE]Test">
                <cmis:value>[NULL]</cmis:value>
            </cmis:propertyString>
        </cmis:properties>
    </cmisra:object>
</atom:entry>

and I would like to have every children of cmis:property so I do

XmlNodeList list = rawData.GetElementsByTagName("cmis:properties")[0].ChildNodes; but I have 5 children. It's appear that every is count as a node.

How can I suppress these breakline to have only the "real children" ?

question from:https://stackoverflow.com/questions/66047206/c-sharp-xmlnode-childnodes-breakline-count-as-node

Answer 1

Thanks to juharr, I found a way with NodeType. Just have to make an if condition with NodeType != NodeType.Whitespace. Thanks you !