Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
228 views
in Technique[技术] by (71.8m points)

python - Pygame mouse clicking detection

I was wondering how to write code that would detect the mouse clicking on a sprite. For example:

if #Function that checks for mouse clicked on Sprite:
    print ("You have opened a chest!")
question from:https://stackoverflow.com/questions/66054694/pygame-falling-digit-block-game-and-using-mouse-to-click-on-digits-in-order-to-a

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

I assume your game has a main loop, and all your sprites are in a list called sprites.

In your main loop, get all events, and check for the MOUSEBUTTONDOWN or MOUSEBUTTONUP event.

while ... # your main loop
  # get all events
  ev = pygame.event.get()

  # proceed events
  for event in ev:

    # handle MOUSEBUTTONUP
    if event.type == pygame.MOUSEBUTTONUP:
      pos = pygame.mouse.get_pos()

      # get a list of all sprites that are under the mouse cursor
      clicked_sprites = [s for s in sprites if s.rect.collidepoint(pos)]
      # do something with the clicked sprites...

So basically you have to check for a click on a sprite yourself every iteration of the mainloop. You'll want to use mouse.get_pos() and rect.collidepoint().

Pygame does not offer event driven programming, as e.g. cocos2d does.

Another way would be to check the position of the mouse cursor and the state of the pressed buttons, but this approach has some issues.

if pygame.mouse.get_pressed()[0] and mysprite.rect.collidepoint(pygame.mouse.get_pos()):
  print ("You have opened a chest!")

You'll have to introduce some kind of flag if you handled this case, since otherwise this code will print "You have opened a chest!" every iteration of the main loop.

handled = False

while ... // your loop

  if pygame.mouse.get_pressed()[0] and mysprite.rect.collidepoint(pygame.mouse.get_pos()) and not handled:
    print ("You have opened a chest!")
    handled = pygame.mouse.get_pressed()[0]

Of course you can subclass Sprite and add a method called is_clicked like this:

class MySprite(Sprite):
  ...

  def is_clicked(self):
    return pygame.mouse.get_pressed()[0] and self.rect.collidepoint(pygame.mouse.get_pos())

So, it's better to use the first approach IMHO.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...