I'm not fully understandable with your code(我对您的代码不完全理解)
But try this code.(但是尝试此代码。)
Its working fine for me(对我来说很好)
Include it in <head> tag(将其包含在<head>标记中)
<head>
<script type="text/javascript">
(function() {
var po = document.createElement('script');
po.type = 'text/javascript'; po.async = true;
po.src = 'https://plus.google.com/js/client:plusone.js';
var s = document.getElementsByTagName('script')[0];
s.parentNode.insertBefore(po, s);
})();
</script>
</head>
Include it in <Body>(将其包含在<Body>)
<body>
<button class="g-signin "
data-scope="https://www.googleapis.com/auth/plus.login https://www.googleapis.com/auth/userinfo.email"
data-requestvisibleactions="http://schemas.google.com/AddActivity"
data-clientId="----YOUR CLIET ID----"
data-accesstype="offline"
data-callback="mycoddeSignIn"
data-theme="dark"
data-cookiepolicy="single_host_origin">
</button>
</body>
and the script for retrieving the data(和用于检索数据的脚本)
dont for get to add this(不要添加它)
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<script type="text/javascript">
var gpclass = (function(){
//Defining Class Variables here
var response = undefined;
return {
//Class functions / Objects
mycoddeSignIn:function(response){
// The user is signed in
if (response['access_token']) {
//Get User Info from Google Plus API
gapi.client.load('plus','v1',this.getUserInformation);
} else if (response['error']) {
// There was an error, which means the user is not signed in.
//alert('There was an error: ' + authResult['error']);
}
},
getUserInformation: function(){
var request = gapi.client.plus.people.get( {'userId' : 'me'} );
request.execute( function(profile) {
var email = profile['emails'].filter(function(v) {
return v.type === 'account'; // Filter out the primary email
})[0].value;
var fName = profile.displayName;
console.log(fName);
console.log(email);
});
}
}; //End of Return
})();
function mycoddeSignIn(gpSignInResponse){
gpclass.mycoddeSignIn(gpSignInResponse);
}
</script>
Check on console the data will be their.(在控制台上检查数据是否正确。)
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