Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
586 views
in Technique[技术] by (71.8m points)

c# - Select entities where ID in int array - WCF Data Services, LINQ

I would like to return a set of entities who has and ID that is contained in a list or array of IDs using LINQ and Data Services. I know how to this using LinqToEF but I am at a loss how to this with Data Services or using OData query conventions for that matter.

My thought is that I would do something like:

int[] intArray = {321456, 321355, 218994, 189232};
var query = (from data in context.Entity
             where intArray.contains(data.ID)
             select data);

Is there any way to accomplish using Data Services / OData? I know I could probably hack it with a Service Operation but I would prefer not to do that.

Cheers.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

Currently OData (the underlying protocol) doesn't support the Contains operation. So that's why the client library does not translate the above query. People are basically using two ways to overcome this limitation: 1) Use service operations as you noted. 2) Construct a where clause dynamically which uses simple comparisons to compare the value to each item from the array. So if the array contains 1, 2, 3, the where would be data.ID == 1 || data.ID == 2 || data.ID == 3 The #2 solution is nice because it's a client side only change. The downside is, that it only works for small arrays. If the array contains too many items the expression gets too long and that leads to all kinds of troubles. The #1 solution doesn't have the size problem, but you need to provide the operation on the server.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...