Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
433 views
in Technique[技术] by (71.8m points)

javascript - extension components to get visit count in firefox's history and bookmarks?

I'd like to to know which interface can be used to get the visit count of each link in firefox's bookmarks and history for developing an extension

I've tried using nav-history-service to get the links for bookmarks and history but can't figure out how to view the visit count.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

This code here will go through the first 10 bookmark entires. If it's a url it checks its .accessCount property which holds the number of times it was visited.

var hs = Cc["@mozilla.org/browser/nav-history-service;1"].getService(Ci.nsINavHistoryService);

var query = hs.getNewQuery();
var options = hs.getNewQueryOptions();

// Query users bookmarks, not history
options.queryType = options.QUERY_TYPE_BOOKMARKS;
// Execute the search and store results
var result = hs.executeQuery(query, options);

// Open the root containerNode and open it
var resultContainerNode = result.root;
// OPEN resultContainerNode
resultContainerNode.containerOpen = true;
// Search results are now child items of this container?
for (var i = 0; i < resultContainerNode.childCount; ++i) {
    var childNode = resultContainerNode.getChild(i);
    if (childNode.type == childNode.RESULT_TYPE_URI) {
        console.log('childNode ' + i + ' is url = ', childNode)
        console.log('times visited = ', childNode.accessCount)
    }
    if (i >= 10) {
        break
    }
}

// CLOSE resultContainerNode
resultContainerNode.containerOpen = false;

gist is here: https://gist.github.com/Noitidart/9729440


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...