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c++ - is `warning C4127` (conditional expression is constant) ever helpful?

While answering this post, I suggested using do {...} while(0) for multiline macros.

On MSVC, I found this code throws up:

warning C4127: conditional expression is constant

To make code warning-free, I need to choose one of these ugly alternatives:

Option 1

#ifdef _MSC_VER
#pragma warning(push)
#pragma warning(disable:4127)
#endif
code_using_macro_that_generates_C4217;
#ifdef _MSC_VER
#pragma warning(pop)
#endif

Option 2
Define my macros as:

#define MULTI_LINE_MACRO do { ... } while(0,0)

or

#define MULTI_LINE_MACRO do { ... } while((void)0,0)

Also called an "owl" by some programmers as (0,0) looks like an owl.

Option 3
Define a new macro WHILE_0 which does not generate a warning and use it instead of while(0)

Problem
I believe all alternatives are more or less horrible. Why does MSVC generate this warning for seemingly correct code and motivate me to add some ugliness to my code to keep the code warning free?

I believe constant expressions in conditionals are perfectly valid and useful, in particular in constructs based on the compiler's ability to optimize out code.

Moreover I don't get a warning C4127 for code like this:

void foo(unsigned bar)
{
    while (bar >= 0)
        ;
} 

My question is: Isn't warning C4127: conditional expression is constant completely useless and doesn't it motivate ugly code? Does this warning ever help writing better code?

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I don't think it is ever useful. On the contrary, there are more false positives than only the do .. while(0) idiom. Think of constructs like

if(sizeof(long) == 8) { /* ... */ }
if(SOME_CONSTANT_MACRO) { /* ... */ }

The former cannot be replaced by #if directives, the latter could, but some coding style guidelines prefer the if version as syntax checking is still done for the dead code (which isn't dead on other platforms or with other compile-time configuration) and some find it nicer to read.

Warnings (other than those required by the standard, most of which should be treated as errors) are usually emitted for code that is valid but is likely to do something else than what's intended. if(0) or things like this look silly, but don't look as if something other than "syntax check this otherwise dead code" was intended. It may puzzle the reader, but it's unambiguous, and I don't see how this could happen accidentally.

From the examples given thus far (I haven't got MSVC to test on my own), it seems like the warning is for constant expressions in the sense of the C language (that is, not something which can be constant-folded but syntactically isn't a constant expression), so it isn't emitted for if(array), or if(function) (what e.g. gcc -Wall does warn about because it's likely intended to be a function call).

while(0,0) is worse, in my opinion, it triggers a warning with gcc -Wall for a left-hand side of a comma operator without side-effects, a warning I can imagine to be occasionally useful (and which usually is easy to avoid). This warning disappears with while((void)0,0).

I suggest turning the warning off.


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