Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
493 views
in Technique[技术] by (71.8m points)

python - Counting consecutive duplicates of strings from a list

I have a Python list of strings such that,

Input:

li = ['aaa','bbb','aaa','abb','abb','bbb','bbb','bbb','aaa','aaa']

What can I do to generate another list counting the number of consecutive repetitions of any string in the list? For the list above the return list resembles:

Expected Output:

li_count = [['aaa',1],['bbb',1]['abb',2],['bbb',3],['aaa',2]]
See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

Use itertools.groupby:

from itertools import groupby
li = ['aaa','bbb','aaa','abb','abb','bbb','bbb','bbb','aaa','aaa']

a = [[i, sum(1 for i in group)] for i, group in groupby(li)]
print(a)
[['aaa', 1], ['bbb', 1], ['aaa', 1], ['abb', 2], ['bbb', 3], ['aaa', 2]]

Thank you @user3483203 for improvement:

a = [[i, len([*group])] for i, group in groupby(li)]

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...