python - Exception handling is ignored with try-except around a function definition

Question

My message "Divide by 0 error" is not going through, instead I'm getting a normal ZeroDivisionError.

#!/usr/bin/python

t = raw_input("do you want to play a game?[y/n]" )

#r = raw_input("Please enter a number")

#e = raw_input("Please enter a number again")

try:
 def di (a, b):
  return  a/b
except ZeroDivisionError:
 print "Divide by 0 Error"

while t == "y":
  u = raw_input("Please enter / sign ")
  if u == "/":
   r = int(raw_input("Please enter a number"))
  try:
   e = int(raw_input("Please enter a number again"))
   print "the answer is", di(r, e)
   t = raw_input("do you want to play a game?[y/n]" )


  except ValueError:
   t = raw_input( "Invalid input, must be a number. Press yes to continue, no stop")

Answer 1

Look at the code more closely:

try:
    def di (a, b):
        return  a/b

except ZeroDivisionError:
    print "Divide by 0 Error"

Your try/except block includes the entire function definition: it applies specifically to defining the function. There is no exception block active while the function is executing from a call.

Use this instead:

def di (a, b):
    try:
        return  a/b
    except ZeroDivisionError:
        print "Divide by 0 Error"