Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
342 views
in Technique[技术] by (71.8m points)

c++ - Assigning value to function returning reference

#include<iostream>
using namespace std;

int &fun()
{
  static int x = 10;
  return x;
}
int main()
{
   fun() = 30;
   cout << fun();
   return 0;
}

Function fun() is returning value by reference but in main() method I am assigning some int to function. Ideally, a compiler should show an error like lvalue required but in above case the program works fine. Why is it so?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

It's loose and sloppy language to say "a function returns something". It's OK as a shorthand if you know how to work with that, but in this case you get confused.

The more correct way to think about it is that you evaluate a function call expression. Doing that gives you a value. A value is either an rvalue or an lvalue (modulo details).

When T is an object type and you evaluate a function that has return type T, you get a value of type T which is an rvalue. On the other hand, if the function has return type T &, you get a value of type T which is an lvalue (and the value is the thing bound to the reference in the return statement).


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

1.4m articles

1.4m replys

5 comments

56.8k users

...