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python - Grouping and auto increment based on columns in pandas

i have a pandas frame that looks like this:

enter image description here

Is there a way to add the numbers in the last column without having to iterate through the data frame?

I was playing with the results of Grouping and auto incrementing group id in pandas but haven't made it work for my purposes

Here is the code to produce the dataframe

import pandas as pd
columns = ['Product','SubProd', 'NeedThis']
Index=['4/20/2012','4/27/2012','5/4/2012','5/11/2012','5/18/2012','4/20/2012',
'4/27/2012','5/4/2012','5/11/2012','5/18/2012','5/25/2012','10/31/2014','11/7/2014',
'11/14/2014','11/21/2014','11/28/2014']
datas = {'Product' : ['A','A','A','A','A','A','A','A','A','A','A','B','B','B','B','B'],
      'SubProd' : ['BL','BL','BL','BL','BL','lk','lk','lk','lk','lk','lk','po','po','po','po','po']}
df = pd.DataFrame(data=datas, index=Index)
print(df)

Output:

           Product SubProd
4/20/2012        A      BL
4/27/2012        A      BL
5/4/2012         A      BL
5/11/2012        A      BL
5/18/2012        A      BL
4/20/2012        A      lk
4/27/2012        A      lk
5/4/2012         A      lk
5/11/2012        A      lk
5/18/2012        A      lk
5/25/2012        A      lk
10/31/2014       B      po
11/7/2014        B      po
11/14/2014       B      po
11/21/2014       B      po
11/28/2014       B      po

Thanks

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In [10]: df['counter'] = df.groupby(['Product','SubProd']).cumcount()+1

In [11]: df
Out[11]: 
           Product SubProd  counter
4/20/2012        A      BL        1
4/27/2012        A      BL        2
5/4/2012         A      BL        3
5/11/2012        A      BL        4
5/18/2012        A      BL        5
4/20/2012        A      lk        1
4/27/2012        A      lk        2
5/4/2012         A      lk        3
5/11/2012        A      lk        4
5/18/2012        A      lk        5
5/25/2012        A      lk        6
10/31/2014       B      po        1
11/7/2014        B      po        2
11/14/2014       B      po        3
11/21/2014       B      po        4
11/28/2014       B      po        5

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