Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
210 views
in Technique[技术] by (71.8m points)

c++ - What is the advantage of using dynamic_cast instead of conventional polymorphism?

We can use Polymorphism (inheritance + virtual functions) in order to generalize different types under a common base-type, and then refer to different objects as if they were of the same type.

Using dynamic_cast appears to be the exact opposite approach, as in essence we are checking the specific type of an object before deciding what action we want to take.

Is there any known example for something that cannot be implemented with conventional polymorphism as easily as it is implemented with dynamic_cast?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

Whenever you find yourself wanting a member function like "IsConcreteX" in a base class (edit: or, more precisely, a function like "ConcreteX *GetConcreteX"), you are basically implementing your own dynamic_cast. For example:

class Movie
{
    // ...
    virtual bool IsActionMovie() const = 0; 
};

class ActionMovie : public Movie
{
    // ...
    virtual bool IsActionMovie() const { return true; }
};

class ComedyMovie : public Movie
{
    // ...
    virtual bool IsActionMovie() const { return false; }
};


void f(Movie const &movie)
{
    if (movie.IsActionMovie())
    {
        // ...
    }
}

This may look cleaner than a dynamic_cast, but on closer inspection, you'll soon realise that you've not gained anything except for the fact that the "evil" dynamic_cast no longer appears in your code (provided you're not using an ancient compiler which doesn't implement dynamic_cast! :)). It's even worse - the "self-written dynamic cast" approach is verbose, error-prone and repetitve, while dynamic_cast will work just fine with no additional code whatsoever in the class definitions.

So the real question should be whether there are situations where it makes sense that a base class knows about a concrete derived class. The answer is: usually it doesn't, but you will doubtlessly encounter such situations.

Think, in very abstract terms, about a component of your software which transmits objects from one part (A) to another (B). Those objects are of type Class1 or Class2, with Class2 is-a Class1.

Class1
  ^
  |
  |
Class2


A - - - - - - - -> B
    (objects)

B, however, has some special handling only for Class2. B may be a completely different part of the system, written by different people, or legacy code. In this case, you want to reuse the A-to-B communication without any modification, and you may not be in a position to modify B, either. It may therefore make sense to explicitly ask whether you are dealing with Class1 or Class2 objects at the other end of the line.

void receiveDataInB(Class1 &object)
{
    normalHandlingForClass1AndAnySubclass(object);
    if (typeid(object) == typeid(Class2))
    {
        additionalSpecialHandlingForClass2(dynamic_cast<Class2 &>(object));
    }
}

Here is an alternative version which does not use typeid:

void receiveDataInB(Class1 &object)
{
    normalHandlingForClass1AndAnySubclass(object);
    Class2 *ptr = dynamic_cast<Class2 *>(&object);
    if (ptr != 0)
    {
        additionalSpecialHandlingForClass2(*ptr);
    }
}

This might be preferable if Class2 is not a leaf class (i.e. if there may be classes further deriving from it).

In the end, it often comes down to whether you are designing a whole system with all its parts from the beginning or have to modify or adapt parts of it at a later stage. But if you ever find yourself confronted with a problem like the one above, you may come to appreciate dynamic_cast as the right tool for the right job in the right situation.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...