Compute the mean of each vector in cell array C.
C = {1:10, [2; 4; 6], []};
averages = cellfun(@mean, C)
This code returns
averages =
5.5000 4.0000 NaN
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该函数就是专门对cell数组进行操作的，个人认为是代替了传统的for循环，和C语言不一个思想，主要是行列化矩阵，一次处理。
比如a = {[1 2 3] [4 5 6]},那么cellfun(@length,a)得到6。线cell2mat也可以吧，然后分别计算，在累加。
Compute the size of each array in C, created in the previous example.
[nrows, ncols] = cellfun(@size, C)
This code returns
nrows =
1 3 0
ncols =
10 1 0
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cellfun中使用自定义函数对cell数组进行处理；既然可以自定义函数，那么cellfun中的的中间部分的参数个数和自定义函数需要的参数数目相同。
还能这么用。
queryNearestNeighborIds = cellfun( @(vector, index) vector(index), queryCandidateIds, queryNearestNeighborIds, \'UniformOutput\', false );
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Create a cell array that contains strings, and abbreviate those strings to the first three characters. Because the output strings are nonscalar, set UniformOutput to false.
days = {\'Monday\', \'Tuesday\', \'Wednesday\', \'Thursday\', \'Friday\'};
abbrev = cellfun(@(x) x(1:3), days, \'UniformOutput\', false)
The syntax @(x) creates an anonymous function. This code returns
abbrev =
\'Mon\' \'Tue\' \'Wed\' \'Thu\' \'Fri\'
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