/**
燕十八 公益PHP培训
课堂地址:YY频道88354001
学习社区:www.zixue.it
**/

mysql> create table a (
-> id char(1),
-> num int
-> )engine myisam charset utf8;
Query OK, 0 rows affected (0.17 sec)

mysql>
mysql> insert into a values (\'a\',5),(\'b\',10),(\'c\',15),(\'d\',10);
Query OK, 4 rows affected (0.00 sec)
Records: 4 Duplicates: 0 Warnings: 0

mysql>
mysql> create table b (
-> id char(1),
-> num int
-> )engine myisam charset utf8;
Query OK, 0 rows affected (0.17 sec)

mysql>
mysql> insert into a values (\'b\',5),(\'c,15),(\'d\',20),(\'e\',99);
\'> \c
\'> \'\c
mysql> insert into b values (\'b\',5),(\'c\',15),(\'d\',20),(\'e\',99);
Query OK, 4 rows affected (0.00 sec)
Records: 4 Duplicates: 0 Warnings: 0

mysql> select * from a;
+------+------+
| id | num |
+------+------+
| a | 5 |
| b | 10 |
| c | 15 |
| d | 10 |
+------+------+
4 rows in set (0.00 sec)

mysql> select * from b;
+------+------+
| id | num |
+------+------+
| b | 5 |
| c | 15 |
| d | 20 |
| e | 99 |
+------+------+
4 rows in set (0.00 sec)

mysql> #可用用左连接来做
mysql> select a.*,b.* from
-> a left join b on a.id=b.id;
+------+------+------+------+
| id | num | id | num |
+------+------+------+------+
| a | 5 | NULL | NULL |
| b | 10 | b | 5 |
| c | 15 | c | 15 |
| d | 10 | d | 20 |
+------+------+------+------+
4 rows in set (0.00 sec)

mysql> #再把上面的结果看成一张临时表,再次from型子查询,计算a.num+b.num的和
mysql> #这个思路,课下同学们自己来试.如遇到坑,查 ifnull函数
mysql> #而且少了e, 只好左连 union 右连,再子查询
mysql>
mysql> #换个思路,先把2张表的数据union到一块,再利用sum()函数来相加
mysql> select * from a;
+------+------+
| id | num |
+------+------+
| a | 5 |
| b | 10 |
| c | 15 |
| d | 10 |
+------+------+
4 rows in set (0.00 sec)

mysql> select * from b;
+------+------+
| id | num |
+------+------+
| b | 5 |
| c | 15 |
| d | 20 |
| e | 99 |
+------+------+
4 rows in set (0.00 sec)

mysql> select * from a
-> union
-> select * from b;
+------+------+
| id | num |
+------+------+
| a | 5 |
| b | 10 |
| c | 15 |
| d | 10 |
| b | 5 |
| d | 20 |
| e | 99 |
+------+------+
7 rows in set (0.00 sec)

mysql> #再sum一下,
mysql> select id,sum(num) from (
->
-> select * from a
-> union
-> select * from b
-> ) as tmp
->
-> group by id;
+------+----------+
| id | sum(num) |
+------+----------+
| a | 5 |
| b | 15 |
| c | 15 |
| d | 30 |
| e | 99 |
+------+----------+
5 rows in set (0.03 sec)

mysql> #c错了,不要去重复
mysql> select id,sum(num) from (
->
-> select * from a
-> union all
-> select * from b
-> ) as tmp
->
-> group by id;
+------+----------+
| id | sum(num) |
+------+----------+
| a | 5 |
| b | 15 |
| c | 30 |
| d | 30 |
| e | 99 |
+------+----------+
5 rows in set (0.00 sec)

mysql> exit

燕十八老师太幽默了, 昨天的视频如下: