• 设为首页
  • 点击收藏
  • 手机版
    手机扫一扫访问
    迪恩网络手机版
  • 关注官方公众号
    微信扫一扫关注
    迪恩网络公众号

C++ remodelCard函数代码示例

原作者: [db:作者] 来自: [db:来源] 收藏 邀请

本文整理汇总了C++中remodelCard函数的典型用法代码示例。如果您正苦于以下问题:C++ remodelCard函数的具体用法?C++ remodelCard怎么用?C++ remodelCard使用的例子?那么恭喜您, 这里精选的函数代码示例或许可以为您提供帮助。



在下文中一共展示了remodelCard函数的3个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于我们的系统推荐出更棒的C++代码示例。

示例1: main

int main(int argc, char** argv){
  struct gameState g;
  int i;
  srand(time(NULL));
  int cardPlays;
  int seed = 0;
  int handPos = 0;
  int randomChoice1, randomChoice2 = 0;

  int handCountPre = 0;
  int randomPlayer;
  int cardCost1,cardCost2;
  int validate = 0;
  
  int k[10] = {adventurer, gardens, embargo, village, minion, mine, cutpurse, 
           sea_hag, tribute, smithy};
  
  cardPlays = 100;
  
  
  
  for(i = 0; i < cardPlays; i ++){
    seed = (rand() % 65535);
	initializeGame(4,k,seed,&g);
  
    randomPlayer = (rand() % 4);
    randomChoice2 = 0;
    handPos = (rand() % 5);
	handCountPre = 0;
	
    
	
	do{
	  randomChoice1 = (rand() % 5);
	} while(randomChoice1 == handPos);
	
	randomChoice2 = gold;//(rand() % 26) + 1;
	cardCost1 = getCost(g.hand[randomPlayer][randomChoice1]);
	cardCost2 = getCost(gold);
	handCountPre = g.handCount[randomPlayer];
	validate = remodelCard(&g, handPos, randomPlayer, randomChoice1, randomChoice2);
	
	if(validate ==0){
	   printf("hand count before %d\n", handCountPre);
	   printf("cost of choice1 = %d\n",cardCost1);
	   printf("cost of choice2 = %d\n",cardCost2);
	   printf("hand count after %d\n", g.handCount[randomPlayer]);
	   //assert(cardCost2 <= (cardCost1+2));
	}
	
	
  }
   
   printf("all test passed");

   return 0;
}
开发者ID:orst-iqbald,项目名称:cs362s15,代码行数:57,代码来源:cardtest4.c


示例2: cardEffect

int cardEffect(int card, int choice1, int choice2, int choice3, struct gameState *state, int handPos, int *bonus)
{
	int i;
	int j;
	int k;
	int index;
	int currentPlayer = whoseTurn(state);
	int nextPlayer = currentPlayer + 1;

	int tributeRevealedCards[2] = {-1, -1};
	int drawntreasure=0;
	if (nextPlayer > (state->numPlayers - 1)){
		nextPlayer = 0;
	}
  
	
	//uses switch to select card and perform actions
	switch( card ) 
		{
		case adventurer:
			return adventurerCard (drawntreasure, state, currentPlayer);
		case council_room:
			return councilRoomCard (currentPlayer, state, handPos);
		case feast:
			return feastCard (currentPlayer, state, choice1);			
		case gardens:
			return -1;			
		case mine:
			return mineCard (currentPlayer, state, choice1, choice2, handPos);
		case remodel:
			return remodelCard (currentPlayer, state, choice1, choice2, handPos);
		case smithy:
			//+3 Cards
			for (i = 0; i < 3; i++)
				{
					drawCard(currentPlayer, state);
				}
			
			//discard card from hand
			discardCard(handPos, currentPlayer, state, 0);
			return 0;
		
		case village:
			//+1 Card
			drawCard(currentPlayer, state);
			
			//+2 Actions
			state->numActions = state->numActions + 2;
			
			//discard played card from hand
			discardCard(handPos, currentPlayer, state, 0);
			return 0;
		
		case baron:
			state->numBuys++;//Increase buys by 1!
			if (choice1 > 0){//Boolean true or going to discard an estate
				int p = 0;//Iterator for hand!
				int card_not_discarded = 1;//Flag for discard set!
				while(card_not_discarded){
					if (state->hand[currentPlayer][p] == estate){//Found an estate card!
						state->coins += 4;//Add 4 coins to the amount of coins
						state->discard[currentPlayer][state->discardCount[currentPlayer]] = state->hand[currentPlayer][p];
						state->discardCount[currentPlayer]++;
						for (;p < state->handCount[currentPlayer]; p++){
							state->hand[currentPlayer][p] = state->hand[currentPlayer][p+1];
						}
						state->hand[currentPlayer][state->handCount[currentPlayer]] = -1;
						state->handCount[currentPlayer]--;
						card_not_discarded = 0;//Exit the loop
					}
					else if (p > state->handCount[currentPlayer]){
						if(DEBUG) {
							printf("No estate cards in your hand, invalid choice\n");
							printf("Must gain an estate if there are any\n");
						}
						if (supplyCount(estate, state) > 0){
							gainCard(estate, state, 0, currentPlayer);
							state->supplyCount[estate]--;//Decrement estates
							if (supplyCount(estate, state) == 0){
								isGameOver(state);
							}
						}
						card_not_discarded = 0;//Exit the loop
					}
			    
					else{
						p++;//Next card
					}
				}
			}
			    
			else{
 /* MUTANT (rep_op) */				if (supplyCount(estate, state) < 0){
					gainCard(estate, state, 0, currentPlayer);//Gain an estate
					state->supplyCount[estate]--;//Decrement Estates
					if (supplyCount(estate, state) == 0){
						isGameOver(state);
					}
				}
			}
//.........这里部分代码省略.........
开发者ID:cs362sp16,项目名称:cs362sp16_minnerp,代码行数:101,代码来源:mutant101490_dominion.c


示例3: cardEffect

int cardEffect(int card, int choice1, int choice2, int choice3, struct gameState *state, int handPos, int *bonus)
{
  	int currentPlayer = whoseTurn(state);
  	int nextPlayer = currentPlayer + 1;
  	int tributeRevealedCards[2] = {-1, -1};
  	int temphand[MAX_HAND];// moved above the if statement
  	int drawntreasure=0;
  	int cardDrawn;
  	int z = 0;// this is the counter for the temp hand

  	if (nextPlayer > (state->numPlayers - 1))
  	{
    	nextPlayer = 0;
  	}

	switch( card )
	{
	  case adventurer:
    	return adventurerCard(&drawntreasure, state, &cardDrawn, &currentPlayer, temphand, &z);
	
	  case council_room:
		return council_roomCard(&currentPlayer, state, &handPos);
	
	  case feast:
    	return feastCard(state, temphand, &currentPlayer, &choice1);
	
	  case gardens:
		return -1;

	  case mine:
    	return mineCard(state, &currentPlayer, &choice1, &choice2, &handPos);
		
	  case remodel:
    	return remodelCard(state, &currentPlayer, &choice1, &choice2, &handPos);
	
	  case smithy:
    	return smithyCard(state, &currentPlayer, &handPos);
	
	  case village:
    	return villageCard(state, &currentPlayer, &handPos);
 	
 	  case baron:
    	return baronCard(state, &currentPlayer, &choice1);

	  case great_hall:
    	return great_hallCard(state, &currentPlayer, &handPos);
	
	  case minion:
    	return minionCard(state, &currentPlayer, &handPos, &choice1, &choice2);
	
	  case steward:
    	return stewardCard(state, &currentPlayer, &handPos,  &choice1, &choice2, &choice3);

	  case tribute:
    	return tributeCard(state, &currentPlayer, &handPos, &nextPlayer, tributeRevealedCards); 

	  case ambassador:
    	return ambassadorCard(state, &currentPlayer, &handPos, &choice1, &choice2);
		
	  case cutpurse:
    	return cutpurseCard(state, &currentPlayer, &handPos);

	  case embargo:
    	return embargoCard(state, &currentPlayer, &handPos, &choice1);

	  case outpost:
    	return outpostCard(state, &currentPlayer, &handPos);

	  case salvager:
    	return salvagerCard(state, &currentPlayer, &handPos, &choice1);

	  case sea_hag:
    	return sea_hagCard(state, &currentPlayer);

	  case treasure_map:
    	return treasure_mapCard(state, &currentPlayer, &handPos);
	}

	return -1;
}
开发者ID:cs362sp16,项目名称:cs362sp16_Johnandr,代码行数:80,代码来源:dominion.c



注:本文中的remodelCard函数示例由纯净天空整理自Github/MSDocs等源码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。


鲜花

握手

雷人

路过

鸡蛋
该文章已有0人参与评论

请发表评论

全部评论

专题导读
上一篇:
C++ remote函数代码示例发布时间:2022-05-30
下一篇:
C++ remap_pfn_range函数代码示例发布时间:2022-05-30
热门推荐
阅读排行榜

扫描微信二维码

查看手机版网站

随时了解更新最新资讯

139-2527-9053

在线客服(服务时间 9:00~18:00)

在线QQ客服
地址:深圳市南山区西丽大学城创智工业园
电邮:jeky_zhao#qq.com
移动电话:139-2527-9053

Powered by 互联科技 X3.4© 2001-2213 极客世界.|Sitemap