本文整理汇总了Python中scipy.cluster.hierarchy.is_valid_linkage函数的典型用法代码示例。如果您正苦于以下问题:Python is_valid_linkage函数的具体用法?Python is_valid_linkage怎么用?Python is_valid_linkage使用的例子?那么恭喜您, 这里精选的函数代码示例或许可以为您提供帮助。
在下文中一共展示了is_valid_linkage函数的6个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于我们的系统推荐出更棒的Python代码示例。
示例1: test_is_valid_linkage_4_and_up
def test_is_valid_linkage_4_and_up(self):
# Tests is_valid_linkage(Z) on linkage on observation sets between
# sizes 4 and 15 (step size 3).
for i in xrange(4, 15, 3):
y = np.random.rand(i*(i-1)//2)
Z = linkage(y)
assert_(is_valid_linkage(Z) == True)
开发者ID:abudulemusa,项目名称:scipy,代码行数:7,代码来源:test_hierarchy.py
示例2: check_is_valid_linkage_various_size
def check_is_valid_linkage_various_size(self, nrow, ncol, valid):
# Tests is_valid_linkage(Z) with linkage matrics of various sizes
Z = np.asarray([[0, 1, 3.0, 2, 5], [3, 2, 4.0, 3, 3]], dtype=np.double)
Z = Z[:nrow, :ncol]
assert_(is_valid_linkage(Z) == valid)
if not valid:
assert_raises(ValueError, is_valid_linkage, Z, throw=True)
开发者ID:Kitchi,项目名称:scipy,代码行数:7,代码来源:test_hierarchy.py
示例3: test_is_valid_linkage_4_and_up_neg_counts
def test_is_valid_linkage_4_and_up_neg_counts(self):
# Tests is_valid_linkage(Z) on linkage on observation sets between
# sizes 4 and 15 (step size 3) with negative counts.
for i in xrange(4, 15, 3):
y = np.random.rand(i*(i-1)//2)
Z = linkage(y)
Z[i//2,3] = -2
assert_(is_valid_linkage(Z) == False)
assert_raises(ValueError, is_valid_linkage, Z, throw=True)
开发者ID:abudulemusa,项目名称:scipy,代码行数:9,代码来源:test_hierarchy.py
示例4: test_is_valid_linkage_empty
def test_is_valid_linkage_empty(self):
# Tests is_valid_linkage(Z) with empty linkage.
Z = np.zeros((0, 4), dtype=np.double)
assert_(is_valid_linkage(Z) == False)
assert_raises(ValueError, is_valid_linkage, Z, throw=True)
开发者ID:abudulemusa,项目名称:scipy,代码行数:5,代码来源:test_hierarchy.py
示例5: test_is_valid_linkage_int_type
def test_is_valid_linkage_int_type(self):
# Tests is_valid_linkage(Z) with integer type.
Z = np.asarray([[0, 1, 3.0, 2],
[3, 2, 4.0, 3]], dtype=np.int)
assert_(is_valid_linkage(Z) == False)
assert_raises(TypeError, is_valid_linkage, Z, throw=True)
开发者ID:abudulemusa,项目名称:scipy,代码行数:6,代码来源:test_hierarchy.py
示例6: _to_dtw_tree
def _to_dtw_tree(linkage, hierarchical_clustering_object, prototypes, prototyping_function='mean'):
"""
Converts a hierarchical clustering linkage matrix `linkage` to hierarchy of `DTWClusterNode`s.
This is a modification of `scipy.cluster.hierarchy.to_tree` function and the code is mostly taken from it.
:param linkage: linkage matrix to convert to the DTW Tree
:param hierarchical_clustering_object: hierarchical clustering object to work with
:param prototyping_function: "reduce" function for prototype calculation, or "mean" to simply use data mean
"""
# Validation
linkage = np.asarray(linkage, order='c')
hierarchy.is_valid_linkage(linkage, throw=True, name='Z')
data = hierarchical_clustering_object.data
labels = data.items
values = data.ix
n = linkage.shape[0] + 1
# Create a list full of None's to store the node objects
d = [None] * (n * 2 - 1)
# Create the nodes corresponding to the n original objects.
for i in xrange(0, n):
index = labels[i]
d[i] = DTWClusterNode(id=index, hierarchical_clustering_object=hierarchical_clustering_object,
prototype=values[index])
nd = None
for i in xrange(0, n - 1):
fi = int(linkage[i, 0])
fj = int(linkage[i, 1])
assert(fi <= i + n)
assert(fj <= i + n)
id = i + n
left = d[fi]
right = d[fj]
dist = linkage[i, 2]
if prototypes:
prototype = prototypes[id]
nd = DTWClusterNode(id=id, hierarchical_clustering_object=hierarchical_clustering_object,
prototype=prototype,
left=left, right=right,
dist=linkage[i, 2])
elif callable(prototyping_function):
prototype = prototyping_function(left.prototype.values, right.prototype.values, left.count, right.count)
nd = DTWClusterNode(id=id, hierarchical_clustering_object=hierarchical_clustering_object,
prototype=prototype,
left=left, right=right,
dist=linkage[i, 2])
elif prototyping_function == 'mean':
nd = DTWClusterNode(id=id, hierarchical_clustering_object=hierarchical_clustering_object,
prototype=None,
left=left, right=right,
dist=linkage[i, 2])
# A bit hacky, but does job. Doing this as to get to use nd.data
nd._prototype = nd.data.mean()
assert(linkage[i, 3] == nd.count)
d[n + i] = nd
return nd, d
开发者ID:lukauskas,项目名称:dgw,代码行数:72,代码来源:analysis.py
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