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Python polys.resultant函数代码示例

原作者: [db:作者] 来自: [db:来源] 收藏 邀请

本文整理汇总了Python中sympy.polys.resultant函数的典型用法代码示例。如果您正苦于以下问题:Python resultant函数的具体用法?Python resultant怎么用?Python resultant使用的例子?那么恭喜您, 这里精选的函数代码示例或许可以为您提供帮助。



在下文中一共展示了resultant函数的7个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于我们的系统推荐出更棒的Python代码示例。

示例1: ratint_logpart

def ratint_logpart(f, g, x, t=None):
    """
    Lazard-Rioboo-Trager algorithm.

    Given a field K and polynomials f and g in K[x], such that f and g
    are coprime, deg(f) < deg(g) and g is square-free, returns a list
    of tuples (s_i, q_i) of polynomials, for i = 1..n, such that s_i
    in K[t, x] and q_i in K[t], and:
                           ___    ___
                 d  f   d  \  `   \  `
                 -- - = --  )      )   a log(s_i(a, x))
                 dx g   dx /__,   /__,
                          i=1..n a | q_i(a) = 0

    Examples
    ========

        >>> from sympy.integrals.rationaltools import ratint_logpart
        >>> from sympy.abc import x
        >>> from sympy import Poly
        >>> ratint_logpart(Poly(1, x, domain='ZZ'),
        ... Poly(x**2 + x + 1, x, domain='ZZ'), x)
        [(Poly(x + 3*_t/2 + 1/2, x, domain='QQ[_t]'),
        ...Poly(3*_t**2 + 1, _t, domain='ZZ'))]
        >>> ratint_logpart(Poly(12, x, domain='ZZ'),
        ... Poly(x**2 - x - 2, x, domain='ZZ'), x)
        [(Poly(x - 3*_t/8 - 1/2, x, domain='QQ[_t]'),
        ...Poly(-_t**2 + 16, _t, domain='ZZ'))]

    See Also
    ========

    ratint, ratint_ratpart
    """
    f, g = Poly(f, x), Poly(g, x)

    t = t or Dummy('t')
    a, b = g, f - g.diff()*Poly(t, x)

    res, R = resultant(a, b, includePRS=True)
    res = Poly(res, t, composite=False)

    assert res, "BUG: resultant(%s, %s) can't be zero" % (a, b)

    R_map, H = {}, []

    for r in R:
        R_map[r.degree()] = r

    def _include_sign(c, sqf):
        if (c < 0) is True:
            h, k = sqf[0]
            sqf[0] = h*c, k

    C, res_sqf = res.sqf_list()
    _include_sign(C, res_sqf)

    for q, i in res_sqf:
        _, q = q.primitive()

        if g.degree() == i:
            H.append((g, q))
        else:
            h = R_map[i]
            h_lc = Poly(h.LC(), t, field=True)

            c, h_lc_sqf = h_lc.sqf_list(all=True)
            _include_sign(c, h_lc_sqf)

            for a, j in h_lc_sqf:
                h = h.quo(Poly(a.gcd(q)**j, x))

            inv, coeffs = h_lc.invert(q), [S(1)]

            for coeff in h.coeffs()[1:]:
                T = (inv*coeff).rem(q)
                coeffs.append(T.as_expr())

            h = Poly(dict(list(zip(h.monoms(), coeffs))), x)

            H.append((h, q))

    return H
开发者ID:AALEKH,项目名称:sympy,代码行数:83,代码来源:rationaltools.py


示例2: log_to_real

def log_to_real(h, q, x, t):
    """
    Convert complex logarithms to real functions.

    Given real field K and polynomials h in K[t,x] and q in K[t],
    returns real function f such that:
                          ___
                  df   d  \  `
                  -- = --  )  a log(h(a, x))
                  dx   dx /__,
                         a | q(a) = 0

    Examples
    ========

        >>> from sympy.integrals.rationaltools import log_to_real
        >>> from sympy.abc import x, y
        >>> from sympy import Poly, sqrt, S
        >>> log_to_real(Poly(x + 3*y/2 + S(1)/2, x, domain='QQ[y]'),
        ... Poly(3*y**2 + 1, y, domain='ZZ'), x, y)
        2*sqrt(3)*atan(2*sqrt(3)*x/3 + sqrt(3)/3)/3
        >>> log_to_real(Poly(x**2 - 1, x, domain='ZZ'),
        ... Poly(-2*y + 1, y, domain='ZZ'), x, y)
        log(x**2 - 1)/2

    See Also
    ========

    log_to_atan
    """
    u, v = symbols('u,v', cls=Dummy)

    H = h.as_expr().subs({t: u + I*v}).expand()
    Q = q.as_expr().subs({t: u + I*v}).expand()

    H_map = collect(H, I, evaluate=False)
    Q_map = collect(Q, I, evaluate=False)

    a, b = H_map.get(S(1), S(0)), H_map.get(I, S(0))
    c, d = Q_map.get(S(1), S(0)), Q_map.get(I, S(0))

    R = Poly(resultant(c, d, v), u)

    R_u = roots(R, filter='R')

    if len(R_u) != R.count_roots():
        return None

    result = S(0)

    for r_u in R_u.keys():
        C = Poly(c.subs({u: r_u}), v)
        R_v = roots(C, filter='R')

        if len(R_v) != C.count_roots():
            return None

        for r_v in R_v:
            if not r_v.is_positive:
                continue

            D = d.subs({u: r_u, v: r_v})

            if D.evalf(chop=True) != 0:
                continue

            A = Poly(a.subs({u: r_u, v: r_v}), x)
            B = Poly(b.subs({u: r_u, v: r_v}), x)

            AB = (A**2 + B**2).as_expr()

            result += r_u*log(AB) + r_v*log_to_atan(A, B)

    R_q = roots(q, filter='R')

    if len(R_q) != q.count_roots():
        return None

    for r in R_q.keys():
        result += r*log(h.as_expr().subs(t, r))

    return result
开发者ID:AALEKH,项目名称:sympy,代码行数:82,代码来源:rationaltools.py


示例3: rsolve_ratio

def rsolve_ratio(coeffs, f, n, **hints):
    """Given linear recurrence operator L of order 'k' with polynomial
       coefficients and inhomogeneous equation Ly = f, where 'f' is a
       polynomial, we seek for all rational solutions over field K of
       characteristic zero.

       This procedure accepts only polynomials, however if you are
       interested in solving recurrence with rational coefficients
       then use rsolve() which will pre-process the given equation
       and run this procedure with polynomial arguments.

       The algorithm performs two basic steps:

           (1) Compute polynomial v(n) which can be used as universal
               denominator of any rational solution of equation Ly = f.

           (2) Construct new linear difference equation by substitution
               y(n) = u(n)/v(n) and solve it for u(n) finding all its
               polynomial solutions. Return None if none were found.

       Algorithm implemented here is a revised version of the original
       Abramov's algorithm, developed in 1989. The new approach is much
       simpler to implement and has better overall efficiency. This
       method can be easily adapted to q-difference equations case.

       Besides finding rational solutions alone, this functions is
       an important part of Hyper algorithm were it is used to find
       particular solution of inhomogeneous part of a recurrence.

       For more information on the implemented algorithm refer to:

       [1] S. A. Abramov, Rational solutions of linear difference
           and q-difference equations with polynomial coefficients,
           in: T. Levelt, ed., Proc. ISSAC '95, ACM Press, New York,
           1995, 285-289

    """
    f = sympify(f)

    if not f.is_polynomial(n):
        return None

    coeffs = map(sympify, coeffs)

    r = len(coeffs)-1

    A, B = coeffs[r], coeffs[0]
    A = A.subs(n, n-r).expand()

    h = Symbol('h', dummy=True)

    res = resultant(A, B.subs(n, n+h), n)

    if not res.is_polynomial(h):
        p, q = res.as_numer_denom()
        res = exquo(p, q, h)

    nni_roots = roots(res, h, filter='Z',
        predicate=lambda r: r >= 0).keys()

    if not nni_roots:
        return rsolve_poly(coeffs, f, n, **hints)
    else:
        C, numers = S.One, [S.Zero]*(r+1)

        for i in xrange(int(max(nni_roots)), -1, -1):
            d = gcd(A, B.subs(n, n+i), n)

            A = exquo(A, d, n)
            B = exquo(B, d.subs(n, n-i), n)

            C *= Mul(*[ d.subs(n, n-j) for j in xrange(0, i+1) ])

        denoms = [ C.subs(n, n+i) for i in range(0, r+1) ]

        for i in range(0, r+1):
            g = gcd(coeffs[i], denoms[i], n)

            numers[i] = exquo(coeffs[i], g, n)
            denoms[i] = exquo(denoms[i], g, n)

        for i in xrange(0, r+1):
            numers[i] *= Mul(*(denoms[:i] + denoms[i+1:]))

        result = rsolve_poly(numers, f * Mul(*denoms), n, **hints)

        if result is not None:
            if hints.get('symbols', False):
                return (simplify(result[0] / C), result[1])
            else:
                return simplify(result / C)
        else:
            return None
开发者ID:Sumith1896,项目名称:sympy-polys,代码行数:93,代码来源:recurr.py


示例4: rsolve_ratio

def rsolve_ratio(coeffs, f, n, **hints):
    """
    Given linear recurrence operator `\operatorname{L}` of order `k`
    with polynomial coefficients and inhomogeneous equation
    `\operatorname{L} y = f`, where `f` is a polynomial, we seek
    for all rational solutions over field `K` of characteristic zero.

    This procedure accepts only polynomials, however if you are
    interested in solving recurrence with rational coefficients
    then use ``rsolve`` which will pre-process the given equation
    and run this procedure with polynomial arguments.

    The algorithm performs two basic steps:

        (1) Compute polynomial `v(n)` which can be used as universal
            denominator of any rational solution of equation
            `\operatorname{L} y = f`.

        (2) Construct new linear difference equation by substitution
            `y(n) = u(n)/v(n)` and solve it for `u(n)` finding all its
            polynomial solutions. Return ``None`` if none were found.

    Algorithm implemented here is a revised version of the original
    Abramov's algorithm, developed in 1989. The new approach is much
    simpler to implement and has better overall efficiency. This
    method can be easily adapted to q-difference equations case.

    Besides finding rational solutions alone, this functions is
    an important part of Hyper algorithm were it is used to find
    particular solution of inhomogeneous part of a recurrence.

    Examples
    ========

    >>> from sympy.abc import x
    >>> from sympy.solvers.recurr import rsolve_ratio
    >>> rsolve_ratio([-2*x**3 + x**2 + 2*x - 1, 2*x**3 + x**2 - 6*x,
    ... - 2*x**3 - 11*x**2 - 18*x - 9, 2*x**3 + 13*x**2 + 22*x + 8], 0, x)
    C2*(2*x - 3)/(2*(x**2 - 1))

    References
    ==========

    .. [1] S. A. Abramov, Rational solutions of linear difference
           and q-difference equations with polynomial coefficients,
           in: T. Levelt, ed., Proc. ISSAC '95, ACM Press, New York,
           1995, 285-289

    See Also
    ========

    rsolve_hyper
    """
    f = sympify(f)

    if not f.is_polynomial(n):
        return None

    coeffs = map(sympify, coeffs)

    r = len(coeffs) - 1

    A, B = coeffs[r], coeffs[0]
    A = A.subs(n, n - r).expand()

    h = Dummy('h')

    res = resultant(A, B.subs(n, n + h), n)

    if not res.is_polynomial(h):
        p, q = res.as_numer_denom()
        res = quo(p, q, h)

    nni_roots = roots(res, h, filter='Z',
        predicate=lambda r: r >= 0).keys()

    if not nni_roots:
        return rsolve_poly(coeffs, f, n, **hints)
    else:
        C, numers = S.One, [S.Zero]*(r + 1)

        for i in xrange(int(max(nni_roots)), -1, -1):
            d = gcd(A, B.subs(n, n + i), n)

            A = quo(A, d, n)
            B = quo(B, d.subs(n, n - i), n)

            C *= Mul(*[ d.subs(n, n - j) for j in xrange(0, i + 1) ])

        denoms = [ C.subs(n, n + i) for i in range(0, r + 1) ]

        for i in range(0, r + 1):
            g = gcd(coeffs[i], denoms[i], n)

            numers[i] = quo(coeffs[i], g, n)
            denoms[i] = quo(denoms[i], g, n)

        for i in xrange(0, r + 1):
            numers[i] *= Mul(*(denoms[:i] + denoms[i + 1:]))

#.........这里部分代码省略.........
开发者ID:alhirzel,项目名称:sympy,代码行数:101,代码来源:recurr.py


示例5: normal

def normal(f, g, n=None):
    """Given relatively prime univariate polynomials 'f' and 'g',
       rewrite their quotient to a normal form defined as follows:

                       f(n)       A(n) C(n+1)
                       ----  =  Z -----------
                       g(n)       B(n)  C(n)

       where Z is arbitrary constant and A, B, C are monic
       polynomials in 'n' with following properties:

           (1) gcd(A(n), B(n+h)) = 1 for all 'h' in N
           (2) gcd(B(n), C(n+1)) = 1
           (3) gcd(A(n), C(n)) = 1

       This normal form, or rational factorization in other words,
       is crucial step in Gosper's algorithm and in difference
       equations solving. It can be also used to decide if two
       hypergeometric are similar or not.

       This procedure will return a tuple containing elements
       of this factorization in the form (Z*A, B, C). For example:

       >>> from sympy import Symbol, normal
       >>> n = Symbol('n', integer=True)

       >>> normal(4*n+5, 2*(4*n+1)*(2*n+3), n)
       (1/4, 3/2 + n, 1/4 + n)

    """
    f, g = map(sympify, (f, g))

    p = f.as_poly(n, field=True)
    q = g.as_poly(n, field=True)

    a, p = p.LC(), p.monic()
    b, q = q.LC(), q.monic()

    A = p.as_basic()
    B = q.as_basic()

    C, Z = S.One, a / b

    h = Dummy('h')

    res = resultant(A, B.subs(n, n+h), n)

    nni_roots = roots(res, h, filter='Z',
        predicate=lambda r: r >= 0).keys()

    if not nni_roots:
        return (f, g, S.One)
    else:
        for i in sorted(nni_roots):
            d = gcd(A, B.subs(n, n+i), n)

            A = quo(A, d, n)
            B = quo(B, d.subs(n, n-i), n)

            C *= Mul(*[ d.subs(n, n-j) for j in xrange(1, i+1) ])

        return (Z*A, B, C)
开发者ID:Aang,项目名称:sympy,代码行数:62,代码来源:gosper.py


示例6: log_to_real

def log_to_real(h, q, x, t):
    """Convert complex logarithms to real functions.

       Given real field K and polynomials h in K[t,x] and q in K[t],
       returns real function f such that:
                              ___
                      df   d  \  `
                      -- = --  )  a log(h(a, x))
                      dx   dx /__,
                             a | q(a) = 0

    """
    u, v = symbols('u,v')

    H = h.as_expr().subs({t:u+I*v}).expand()
    Q = q.as_expr().subs({t:u+I*v}).expand()

    H_map = collect(H, I, evaluate=False)
    Q_map = collect(Q, I, evaluate=False)

    a, b = H_map.get(S(1), S(0)), H_map.get(I, S(0))
    c, d = Q_map.get(S(1), S(0)), Q_map.get(I, S(0))

    R = Poly(resultant(c, d, v), u)

    R_u = roots(R, filter='R')

    if len(R_u) != R.count_roots():
        return None

    result = S(0)

    for r_u in R_u.iterkeys():
        C = Poly(c.subs({u:r_u}), v)
        R_v = roots(C, filter='R')

        if len(R_v) != C.count_roots():
            return None

        for r_v in R_v:
            if not r_v.is_positive:
                continue

            D = d.subs({u:r_u, v:r_v})

            if D.evalf(chop=True) != 0:
                continue

            A = Poly(a.subs({u:r_u, v:r_v}), x)
            B = Poly(b.subs({u:r_u, v:r_v}), x)

            AB = (A**2 + B**2).as_expr()

            result += r_u*log(AB) + r_v*log_to_atan(A, B)

    R_q = roots(q, filter='R')

    if len(R_q) != q.count_roots():
        return None

    for r in R_q.iterkeys():
        result += r*log(h.as_expr().subs(t, r))

    return result
开发者ID:101man,项目名称:sympy,代码行数:64,代码来源:rationaltools.py


示例7: ratint_logpart

def ratint_logpart(f, g, x, t=None):
    """Lazard-Rioboo-Trager algorithm.

       Given a field K and polynomials f and g in K[x], such that f and g
       are coprime, deg(f) < deg(g) and g is square-free, returns a list
       of tuples (s_i, q_i) of polynomials, for i = 1..n, such that s_i
       in K[t, x] and q_i in K[t], and:
                               ___    ___
                     d  f   d  \  `   \  `
                     -- - = --  )      )   a log(s_i(a, x))
                     dx g   dx /__,   /__,
                              i=1..n a | q_i(a) = 0

    """
    f, g = Poly(f, x), Poly(g, x)

    t = t or Dummy('t')
    a, b = g, f - g.diff()*Poly(t, x)

    R = subresultants(a, b)

    res = Poly(resultant(a, b), t, composite=False)

    R_map, H = {}, []

    for r in R:
        R_map[r.degree()] = r

    def _include_sign(c, sqf):
        if c < 0:
            h, k = sqf[0]
            sqf[0] = h*c, k

    C, res_sqf = res.sqf_list()
    _include_sign(C, res_sqf)

    for q, i in res_sqf:
        _, q = q.primitive()

        if g.degree() == i:
            H.append((g, q))
        else:
            h = R_map[i]
            h_lc = Poly(h.LC(), t, field=True)

            c, h_lc_sqf = h_lc.sqf_list(all=True)
            _include_sign(c, h_lc_sqf)

            for a, j in h_lc_sqf:
                h = h.quo(Poly(a.gcd(q)**j, x))

            inv, coeffs = h_lc.invert(q), [S(1)]

            for coeff in h.coeffs()[1:]:
                T = (inv*coeff).rem(q)
                coeffs.append(T.as_expr())

            h = Poly(dict(zip(h.monoms(), coeffs)), x)

            H.append((h, q))

    return H
开发者ID:101man,项目名称:sympy,代码行数:62,代码来源:rationaltools.py



注:本文中的sympy.polys.resultant函数示例由纯净天空整理自Github/MSDocs等源码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。


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