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VB.NET Enumerable.Min方法代码示例

原作者: [db:作者] 来自: [db:来源] 收藏 邀请

本文整理汇总了VB.NET中System.Linq.Enumerable.Min方法的典型用法代码示例。如果您正苦于以下问题:VB.NET Enumerable.Min方法的具体用法?VB.NET Enumerable.Min怎么用?VB.NET Enumerable.Min使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。



在下文中一共展示了Enumerable.Min方法的4个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于我们的系统推荐出更棒的VB.NET代码示例。

示例1: grades

Dim grades() As Nullable(Of Integer) = {78, 92, Nothing, 99, 37, 81}
Dim min As Nullable(Of Integer) = grades.Min()

' Display the output.
Console.WriteLine($"The lowest grade is {min}")
开发者ID:VB.NET开发者,项目名称:System.Linq,代码行数:5,代码来源:Enumerable.Min

输出:

The lowest grade is 37


示例2: doubles

' Create an array of double values.
Dim doubles() As Double = {1.5E+104, 9.0E+103, -2.0E+103}

' Determine the smallest number in the array.
Dim min As Double = doubles.Min()

' Display the result.
Console.WriteLine($"The smallest number is {min}")
开发者ID:VB.NET开发者,项目名称:System.Linq,代码行数:8,代码来源:Enumerable.Min

输出:

The smallest number is -2E+103


示例3: MinEx4

Structure Pet
    Public Name As String
    Public Age As Integer
End Structure

Sub MinEx4()
    ' Create an array of Pet objects.
    Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8},
                     New Pet With {.Name = "Boots", .Age = 4},
                     New Pet With {.Name = "Whiskers", .Age = 1}}

    ' Find the youngest pet by passing a 
    ' lambda expression to the Min() method.
    Dim min As Integer = pets.Min(Function(pet) pet.Age)

    ' Display the result.
    Console.WriteLine($"The youngest pet is age {min}")
End Sub
开发者ID:VB.NET开发者,项目名称:System.Linq,代码行数:18,代码来源:Enumerable.Min

输出:

The youngest pet is age 1


示例4: Pet

' This class implements IComparable 
' and has a custom 'CompareTo' implementation.
Class Pet
    Implements IComparable(Of Pet)

    Public Name As String
    Public Age As Integer

    ''' <summary>
    ''' Compares this Pet's age to another Pet's age.
    ''' </summary>
    ''' <param name="other">The Pet to compare this Pet to.</param>
    ''' <returns>-1 if this Pet's age is smaller,
    ''' 0 if the Pets' ages are equal,
    ''' or 1 if this Pet's age is greater.</returns>
    Function CompareTo(ByVal other As Pet) As Integer _
    Implements IComparable(Of Pet).CompareTo

        If (other.Age > Me.Age) Then
            Return -1
        ElseIf (other.Age = Me.Age) Then
            Return 0
        Else
            Return 1
        End If
    End Function
End Class

Sub MinEx3()
    ' Create an array of Pet objects.
    Dim pets() As Pet = {New Pet With {.Name = "Barley", .Age = 8},
                     New Pet With {.Name = "Boots", .Age = 4},
                     New Pet With {.Name = "Whiskers", .Age = 1}}

    ' Determine the "minimum" pet in the array,
    ' according to the custom CompareTo() implementation.
    Dim min As Pet = pets.Min()

    ' Display the result.
    Console.WriteLine($"The 'minimum' pet is {min.Name}")
End Sub
开发者ID:VB.NET开发者,项目名称:System.Linq,代码行数:41,代码来源:Enumerable.Min

输出:

The 'minimum' pet is Whiskers



注:本文中的System.Linq.Enumerable.Min方法示例整理自Github/MSDocs等源码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。


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