本文整理汇总了VB.NET中System.Array.FindLastIndex方法的典型用法代码示例。如果您正苦于以下问题:VB.NET Array.FindLastIndex方法的具体用法?VB.NET Array.FindLastIndex怎么用?VB.NET Array.FindLastIndex使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类System.Array 的用法示例。
在下文中一共展示了Array.FindLastIndex方法的1个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于我们的系统推荐出更棒的VB.NET代码示例。
示例1: Example
Public Class Example
Public Shared Sub Main()
Dim dinosaurs() As String = { "Compsognathus", _
"Amargasaurus", "Oviraptor", "Velociraptor", _
"Deinonychus", "Dilophosaurus", "Gallimimus", _
"Triceratops" }
Console.WriteLine()
For Each dinosaur As String In dinosaurs
Console.WriteLine(dinosaur)
Next
Console.WriteLine(vbLf & _
"Array.FindLastIndex(dinosaurs, AddressOf EndsWithSaurus): {0}", _
Array.FindLastIndex(dinosaurs, AddressOf EndsWithSaurus))
Console.WriteLine(vbLf & _
"Array.FindLastIndex(dinosaurs, 4, AddressOf EndsWithSaurus): {0}", _
Array.FindLastIndex(dinosaurs, 4, AddressOf EndsWithSaurus))
Console.WriteLine(vbLf & _
"Array.FindLastIndex(dinosaurs, 4, 3, AddressOf EndsWithSaurus): {0}", _
Array.FindLastIndex(dinosaurs, 4, 3, AddressOf EndsWithSaurus))
End Sub
' Search predicate returns true if a string ends in "saurus".
Private Shared Function EndsWithSaurus(ByVal s As String) _
As Boolean
' AndAlso prevents evaluation of the second Boolean
' expression if the string is so short that an error
' would occur.
If (s.Length > 5) AndAlso _
(s.Substring(s.Length - 6).ToLower() = "saurus") Then
Return True
Else
Return False
End If
End Function
End Class
开发者ID:VB.NET开发者,项目名称:System,代码行数:43,代码来源:Array.FindLastIndex 输出:
Compsognathus
Amargasaurus
Oviraptor
Velociraptor
Deinonychus
Dilophosaurus
Gallimimus
Triceratops
Array.FindLastIndex(dinosaurs, AddressOf EndsWithSaurus): 5
Array.FindLastIndex(dinosaurs, 4, AddressOf EndsWithSaurus): 1
Array.FindLastIndex(dinosaurs, 4, 3, AddressOf EndsWithSaurus): -1
注:本文中的System.Array.FindLastIndex方法示例由纯净天空整理自Github/MSDocs等源码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。 |
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