SQL 判断给定日期值(或时间段)所在星期的星期一和星期天的日期 ...

原作者: [db:作者] 来自: [db:来源] 收藏邀请

一、给定一个日期值，求出此日期所在星期的星期一和星期天的日期数据
例如给定一个日期 2010-09-01，求出它所在星期的星期一是2010-08-30，星期天是2010-09-05

Function创建如下:

 
USE [MSSQL] 
GO 
SET ANSI_NULLS ON 
GO 
SET QUOTED_IDENTIFIER ON 
GO 
CREATE FUNCTION [dbo].[My_OneDay_GetWeekFirstAndEndDay](@tmpDate DATETIME) 
RETURNS @tmpTable TABLE(FirstDay DATETIME , EndDay DATETIME) 
AS 
BEGIN 
INSERT INTO @tmpTable 
SELECT a.FirstDay,b.EndDay FROM ( 
SELECT 1 AS ID,DATEADD(wk, DATEDIFF(wk,0,@tmpDate), 0) AS FirstDAy 
) a 
LEFT JOIN ( 
SELECT 1 AS ID,DATEADD(wk, DATEDIFF(wk,0,@tmpDate), 6) AS EndDay 
) b 
ON a.ID = b.ID 
RETURN 
End 

Function测试:

复制代码代码如下:

SELECT * from My_OneDay_GetWeekFirstAndEndDay('2010-09-01')

二、以上面单个日期搜索为基础，由用户输入两个参数，一个是开始日期，一个结束日期，根据这两个参数，求出在此时期段内的所有星期的星期一和星期天的日期表并排序。
例如开始日期是2011-09-01,结束日期是2011-10-06，我们就可以得到此星期表如下:
WeekOrder FirstDay EndDay
1 2011-08-29 00:00:00.000 2011-09-04 00:00:00.000
2 2011-09-05 00:00:00.000 2011-09-11 00:00:00.000
3 2011-09-12 00:00:00.000 2011-09-18 00:00:00.000
4 2011-09-19 00:00:00.000 2011-09-25 00:00:00.000
5 2011-09-26 00:00:00.000 2011-10-02 00:00:00.000
6 2011-10-03 00:00:00.000 2011-10-09 00:00:00.000

Function创建如下:

复制代码代码如下:

 
USE [MSSQL] 
GO 
SET ANSI_NULLS ON 
GO 
SET QUOTED_IDENTIFIER ON 
GO 
CREATE FUNCTION [dbo].[MY_Range_GetWeekFirstAndEndDays](@tmpDateSTART DATETIME,@tmpDateEND DATETIME) 
RETURNS @tmpTable TABLE(WeekOrder INT,FirstDay DATETIME , EndDay DATETIME) 
AS 
BEGIN 
DECLARE @tmpDate DATETIME 
DECLARE @index INT 
SET @tmpDate=@tmpDateSTART 
SET @index=1 
WHILE @tmpDate <=@tmpDateEND 
BEGIN 
INSERT INTO @tmpTable 
SELECT @index,a.FirstDay,b.EndDay FROM ( 
SELECT 1 AS ID,DATEADD(wk, DATEDIFF(wk,0,@tmpDate), 0) AS FirstDAy) a 
LEFT JOIN ( 
SELECT 1 AS ID,DATEADD(wk, DATEDIFF(wk,0,@tmpDate), 6) AS EndDay) b 
ON a.ID = b.ID 

SET @tmpDate=DATEADD(DAY,7,@tmpDate) 
SET @index=@index+1 
END 
RETURN 
End 