I hope that someone familiar with Python's compilation / run-time procedures could shed some light on my question relating to how Python compiles decorator functions.
Within my sample code, I've included a testing print statement in the "writeit" decorator just before the logtofile closure is defined. If you run the entire code that I've provided, the "testing" print statement in writeit is called for each @writeit decorator defined in the Customer class-- before writeit is ever used.
Why is logtofile being called at compile time? Could someone please explain this behavior?
def writeit(func):
print('testing')
def logtofile(customer, *arg, **kwargs):
print('logtofile')
result = func(customer, *arg, **kwargs)
with open('dictlog.txt','w') as myfile:
myfile.write(func.__name__)
return result
return logtofile
class Customer(object):
def __init__(self,firstname,lastname,address,city,state,zipcode):
self._custinfo = dict(firstname=firstname,lastname=lastname,address=address,city=city,state=state,zipcode=zipcode)
@writeit
def setFirstName(self,firstname):
print('setFirstName')
self._custinfo['firstname']=firstname
@writeit
def setLastName(self,lastname):
print('setLastName')
self._custinfo['lastname']=lastname
@writeit
def setAddress(self,address):
print('setAddress')
self._custinfo['address']=address
def main():
cust1 = Customer('Joe','Shmoe','123 Washington','Washington DC','DC','12345')
cust1.setFirstName('Joseph')
cust1.setLastName('Shmoestein')
if(__name__ == '__main__'): main()
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