javascript - return largest phone number in JS array

Question

I have to return the largest phone number,not index, from an array in Javascript. I am trying to remove the non digit characters then find largest number. I am new and not experienced with the syntax. Alot of examples show parts of my problem. I don't know how to connect them into one function and how to return the answer. Please help me out. Heres what I have:

function myFunction(array) {
    var largest = array.replace(/D/g, '');
    for (var i = 0; i < array.length; i++) {
        if (largest < array[i]) {
            largest = array[i];
        }
    }
    console.log(largest);
}

myFunction([509 - 111 - 1111, 509 - 222 - 2222, 509 - 333 - 3333]);

Answer 1

As suggested by fellow friends, you need to wrap the phone numbers within quotes as they are not numbers. Once you have done that, try following logic to extract the desired results for you

function myFunction(array) {

  // Creates the number array against the telephone numbers 
  var numberArray = array.map(function(phone){
     return parseInt(phone.replace(/D/g, ''));
  });


  // Now it is simple to compare and find the largest in an array of numbers
  var largestIndex = 0;
  var largestNumber = numberArray[0];

  for (var i = 0; i < numberArray.length; i++) {
     if (largestNumber < numberArray[i]) {
        largestNumber = numberArray[i];
        largestIndex = i;
     }
  }
  // Fetch the value against the largest index from the phone numbers array
  console.log(array[largestIndex]);
}

myFunction(["509 - 111 - 1111", "509 - 222 - 2222", "509 - 333 - 3333", "509 - 333 - 3332"]);