Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
509 views
in Technique[技术] by (71.8m points)

indexing - How often should the indexes be rebuilt in our SQL Server database?

Currently our database has size 10 GB and is growing by around 3 GB per month. Often I hear that one should from time to time rebuild the indexes, to improve the query execution time. So how often should I rebuild the indexes in the given scenario?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

There's a general consensus that you should reorganize ("defragment") your indices as soon as index fragmentation reaches more than 5 (sometimes 10%), and you should rebuild them completely when it goes beyond 30% (at least that's the numbers I've heard advocated in a lot of places).

Michelle Ufford (a.k.a. "SQL Fool") has an automated index defrag script, which uses those exact limits for deciding when to reorganize or rebuild an index.

Also see Brad McGehee's tips on rebuild indexes with some good thoughts and tips on how to deal with index rebuilding.


I use this script here (can't remember when I got this from - whoever it was: many thanks! Really helpful stuff) to display the index fragmentation on all your indices in a given database:

SELECT 
    t.NAME 'Table name',
    i.NAME 'Index name',
    ips.index_type_desc,
    ips.alloc_unit_type_desc,
    ips.index_depth,
    ips.index_level,
    ips.avg_fragmentation_in_percent,
    ips.fragment_count,
    ips.avg_fragment_size_in_pages,
    ips.page_count,
    ips.avg_page_space_used_in_percent,
    ips.record_count,
    ips.ghost_record_count,
    ips.Version_ghost_record_count,
    ips.min_record_size_in_bytes,
    ips.max_record_size_in_bytes,
    ips.avg_record_size_in_bytes,
    ips.forwarded_record_count
FROM 
    sys.dm_db_index_physical_stats(DB_ID(), NULL, NULL, NULL, 'DETAILED') ips
INNER JOIN  
    sys.tables t ON ips.OBJECT_ID = t.Object_ID
INNER JOIN  
    sys.indexes i ON ips.index_id = i.index_id AND ips.OBJECT_ID = i.object_id
WHERE
    AVG_FRAGMENTATION_IN_PERCENT > 0.0
ORDER BY
    AVG_FRAGMENTATION_IN_PERCENT, fragment_count
    

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...