Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
362 views
in Technique[技术] by (71.8m points)

Setting one object equal to another object with the assignment operator in Javascript

I'm coming to javascript from C background. In javascript, when I use the assignment operator to assign one object to another, does it copy the values from one to the another, or do they both now point to the same data?. Or does the assignment operator do anything in this case?

function point_type()
 {
 this.x = 0;
 this.y = 0;
 }

var pnt1 = new point_type();
var pnt2 = new point_type();

pnt1.x = 4;
pnt1.y = 5;

pnt2 = pnt1;

pnt1.x = 8;
pnt2.y = 9;

In the example above, does pnt2.x now equal 8, or does it still equal 4, or does it still equal 0?

Yes, I realize I can test this myself, and I will be doing that while I wait for the community to come up with an answer. However, I'm hoping the answer to my question will go one step past just answering this one example and might shine some light on how javascript objects work and some best practices.

Follow up question:
The answer seems to be that the reference is copied. pnt2 and pnt1 now point to the same data. Is it possible to set up my object so that the values are copied? How is this usually accomplished in javascript? Clearly I don't want to set each attribute individually every time I need to copy this object.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

Whenever I need to copy one object to another in JS, I just cast it to a primitive:

var newObject = JSON.stringify(oldObject);

Then when I need to use it:

var evenNewerObj = JSON.parse(newObject);

Hope this helps someone.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...