Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
844 views
in Technique[技术] by (71.8m points)

c - Why does my compiler not accept fork(), despite my inclusion of <unistd.h>?

Here's my code (created just to test fork()):

#include <stdio.h>  
#include <ctype.h>
#include <limits.h>
#include <string.h>
#include <stdlib.h>
#include <unistd.h> 

int main()
{   
    int pid;     
    pid=fork();

    if (pid==0) {
        printf("I am the child
");
        printf("my pid=%d
", getpid());
    }

    return 0;
}

I get following warnings:

warning: implicit declaration of function 'fork'
undefined reference to 'fork'

What is wrong with it?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

unistd.h and fork are part of the POSIX standard. They aren't available on windows (text.exe in your gcc command hints that's you're not on *nix).

It looks like you're using gcc as part of MinGW, which does provide the unistd.h header but does not implement functions like fork. Cygwin does provide implementations of functions like fork.

However, since this is homework you should already have instructions on how to obtain a working environment.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...