javascript - How to achieve a debounce service on input keyup event in angular2 with rxjs

Question

I am trying to call to a service on input key-up event.

The HTML

<input placeholder="enter name" (keyup)='onKeyUp($event)'>

Below is the onKeyUp() function

onKeyUp(event) {
    let observable = Observable.fromEvent(event.target, 'keyup')
        .map(value => event.target.value)
        .debounceTime(1000)
        .distinctUntilChanged()
        .flatMap((search) => {
            // call the service
        });
    observable.subscribe((data) => {
        // data
    });
}

It was found from the network tab of the browser that, it is calling the key-up function on every key-up event(as it is supposed to do), but what I am trying to achieve is a debounce time of 1sec between each service call. Also, the event is triggered if I move the arrow key move.

plunkr link

Answer 1

So the chain is really correct but the problem is that you're creating an Observable and subscribe to it on every keyup event. That's why it prints the same value multiple times. There're simply multiple subscriptions which is not what you want to do.

There're obviously more ways to do it correctly, for example:

@Component({
  selector: 'my-app',
  template: `
    <div>
      <input type="text" (keyup)='keyUp.next($event)'>
    </div>
  `,
})
export class App implements OnDestroy {

  public keyUp = new Subject<KeyboardEvent>();

  private subscription: Subscription;

  constructor() {
    this.subscription = this.keyUp.pipe(
      map(event => event.target.value),
      debounceTime(1000),
      distinctUntilChanged(),
      mergeMap(search => of(search).pipe(
        delay(500),
      )),
    ).subscribe(console.log);
  }

  ngOnDestroy(): void {
    this.subscription.unsubscribe();
  }
}

See your updated demo: http://plnkr.co/edit/mAMlgycTcvrYf7509DOP

Jan 2019: Updated for RxJS 6