Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
1.2k views
in Technique[技术] by (71.8m points)

How to define an enum in OpenAPI (Swagger)?

Does anyone know how to define possible 'enum' values in an OpenAPI 2.0 definition so that they will be displayed in the Model tab of Swagger UI? Example here: https://petstore.swagger.io/#!/pet/addPet has an enum option for the status property. How to do define such an enum in OpenAPI 2.0?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

"enum" works like this in OpenAPI 2.0:

      {
        "in": "query",
        "name": "sample",
        "description": "a sample parameter with an enum value",
        "type": "string",
        "enum": [ "1", "2"],
        "required": true
      }

and in OpenAPI 3.0:

      {
        "in": "query",
        "name": "sample",
        "description": "a sample parameter with an enum value",
        "schema": {
          "type": "string",
          "enum": [ "1", "2"]
        },
        "required": true
      }

As you can see, there's a query parameter called sample of type string, and has an enum stating two possible values. In this case, the sample states the parameter is required, so the UI will not show an empty value as an option.

For a minimal working sample, try this:

{
  "swagger": "2.0",
  "info": {
    "title": "title",
    "description": "descriptor",
    "version": "0.1"
  },
  "paths": {
    "/sample": {
      "post": {
        "description": "sample",
        "parameters": [
          {
            "in": "query",
            "name": "sample",
            "description": "a sample parameter with an enum value",
            "type": "string",
            "enum": [
              "1",
              "2"
            ],
            "required": true
          }
        ],
        "responses": {
          "200": {
            "description": "Successful request."
          }
        }
      }
    }
  }
}

To test it locally, you can declare a variable (for example spec) in your javascript, and pass it into the SwaggerUi object.

  var spec = { ... };

  window.swaggerUi = new SwaggerUi({
    url: url,
    spec: spec,
    dom_id: "swagger-ui-container",
    supportedSubmitMethods: ['get', 'post', 'put', 'delete'],
    onComplete: function(swaggerApi, swaggerUi){
    ...

The url parameter will be ignored in this case.

Eventually, the output looks like this:

enter image description here


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

1.4m articles

1.4m replys

5 comments

56.9k users

...