Can we see the template instantiated code by C++ compiler

Question

is there a way to know the compiler instantiated code for a template function or a class in C++

Assume I have the following piece of code

template < class T> T add(T a, T b){
            return a+b;
}

now when i call

add<int>(10,2); 

I would like to know the function that compiler creates for int specific version.

I am using G++, VC++. It will be helpful if some can help me point out the compiler options to achieve this.

Hope the question is clear. Thanks in advance.

Answer 1

Clang (https://clang.llvm.org/) can pretty-print AST of instantiated template:

For your example:

test.cpp

template < class T> T add(T a, T b){
    return a+b;
}

void tmp() {
    add<int>(10,2); 
}

Command to pretty-print AST:

$ clang++ -Xclang -ast-print -fsyntax-only test.cpp

Clang-5.0 output:

template <class T> T add(T a, T b) {
    return a + b;
}
template<> int add<int>(int a, int b) {
    return a + b;
}
void tmp() {
    add<int>(10, 2);
}