Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
115 views
in Technique[技术] by (71.8m points)

Why does jQuery throw the error `fadeOut is not a function'?

I am using jQuery and put this code in my javascript:

function HideMe(itemID) {
    var myDiv = 'item_' + itemID;
    $(myDiv).fadeOut("slow");
}

But its giving me this error: fadeOut is not a function.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

This will happen if you're using the "slim" version of jQuery. Only the "full" version of jQuery includes animation effects.

Try grabbing the "full" version of jQuery from the jQuery downloads page and including that in your page (or including a full version of jQuery from a CDN from your page).


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...