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in Technique[技术] by (71.8m points)

instantiate a class from a variable in PHP?

I know this question sounds rather vague so I will make it more clear with an example:

$var = 'bar';
$bar = new {$var}Class('var for __construct()'); //$bar = new barClass('var for __construct()');

This is what I want to do. How would you do it? I could off course use eval() like this:

$var = 'bar';
eval('$bar = new '.$var.'Class('var for __construct()');');

But I'd rather stay away from eval(). Is there any way to do this without eval()?

Question&Answers:os

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by (71.8m points)

Put the classname into a variable first:

$classname=$var.'Class';

$bar=new $classname("xyz");

This is often the sort of thing you'll see wrapped up in a Factory pattern.

See Namespaces and dynamic language features for further details.


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