python - How to load a list, add an element to it and then store it again?

Question

I'm using Python 3.8

I want to load a list of no integer value that is in a file ex: ["a", "b", "c"], no matter the kind of the file. Then I want to add to this list an element ex "d" so the final list would be ["a", "b", "c", "d"].

Next, this list will be written in the same file replacing what was inside. In this way a will have a clean file with the updated list.

This process will be repeated many times.

I thought it was a simple process and maybe it is, but I can't find a way.

question from:https://stackoverflow.com/questions/65860350/how-to-load-a-list-add-an-element-to-it-and-then-store-it-again

Answer 1

Doing what you want is possible. But you shoul use instead le library pickle. First import picle

import pickle

For saving the variable you can use this

def saver(obj): #Pass the object you want to save
    pickle_file = open("data.pickle", "wb")
    pickle.dump(obj,pickle_file)
    pickle_file.close

Then to load :

def loader():

    pickle_file = pickle_file = open("data.pickle", "rb")
    data = pickle.load(pickle_file)
    pickle_file.close()
    return data

Exemple:

saver([1,2,3,4])
liste = loader()
print(liste)