simplifying Boolean expression A'BC + AB'C + ABC'

Question

Need help here, whats the simplified form of this Boolean expression? I'm a little confused about this, help me guys!

A'BC + AB'C + ABC'

question from:https://stackoverflow.com/questions/65868553/simplifying-boolean-expression-abc-abc-abc

Answer 1

ABC A'BC + AB'C + ABC'
000 0
001 0
010 0
011 1
100 0
101 1
110 1
111 0

This cannot be simplified, see *Karnaugh map*.

But using other operators, there are simpler forms:

• Exclusive OR ^: A'BC + A(B^C)
• Bit count: #[A, B, C] = 2