python - Count how many times a value is exceeded in a list

Question

in a Python list, I need to count how many times a value is exceeded.

This code counts how many values exceed a limit. Suppose I have this example, and I want to count how many time 2 is exceeded.

array = [1, 2, 3, 4, 1, 2, 3, 1]
a = pd.Series(array)
print(len(a[a >= 2]))
# prints 5

How can I collapse consecutive values, such that 2 is returned instead?

question from:https://stackoverflow.com/questions/65682069/count-how-many-times-a-value-is-exceeded-in-a-list

Answer 1

First compute exc = a.ge(2) - a Series answering the question: Does the current value is >= 2.

Then, to get a number of sequences of "exceeding" elements, run:

result = (exc.shift().ne(exc) & exc).sum()

The result for your data is just 2.