python - Putting parser.parse_args() in try except block

Question

Currently my endpoint look like this:

def post(cls):        
    data = cls.parser.parse_args()
    try: 
        #some logic
    except ValueError as e:
         return {"message": str(e)}, 400
    except Exception as e:
        raise InternalServerError(e)

My problem is that if I were to put parse_args() in try block the message generated by parser validation is ignored and exception gets caught in my logic - which ends up in response that does not contain any messsage about validation.

I could keep it out of try block but my idea is to get rid of try except block by supplying a wrapper - that will wrap parsing too...

question from:https://stackoverflow.com/questions/65644381/putting-parser-parse-args-in-try-except-block

Answer 1

Waitting for answers