php - Using a switch statement to append classname on dropdown

Question

So I have a menu that I converted over to a mega menu and it works great, but I wanted to clean the code up a bit and get some input from professionals here.

Here is the PHP code:

<?php $count = count($sub_items);
$parent_columns = "columns";
$child_column = "column";
switch ($count) {
    case 1:
    case 2:
    case 3:
        $parent_columns .= " is-justify-content-center";
        $child_column .= " is-one-quarter";
        break;
    default:
        $parent_columns .= " is-multiline";
        $child_column = ($count >= 4) ? " column is-one-quarter" : " column";
} ?>

• The variable $sub_items returns an array and I grab the count using count().
• Then I base the parent and child variables on cases, 1-3 are the same, while 4+ is different classes.

Then I pull them inside my <div> like this:

<div class="<?= $parent_columns ?>"></div>
<div class="<?= $child_column; ?>"></div>

Does anyone know a better method with my PHP code? Are there other better methods than a switch statement? All help would be appreciated.

Answer 1

Instead of multiple cases you can try this.

<?php
$count = count($sub_items);
$parent_columns = "columns";
$child_column = "column";
if($count <= 3) {
    $parent_columns .= " is-justify-content-center";
    $child_column .= " is-one-quarter";
} else {
    $parent_columns .= " is-multiline";
    $child_column = ($count >= 4) ? " column is-one-quarter" : " column";
}