ios - 基于另一个 UIPickerView 显示 UIPickerView
<p><p>我有两个不同的 <code>UIPickerView</code> 用户选择第一个 <code>UIPickerView</code> 并从第一个选择器的 <code>didSelectRow</code> 中，我得到第二个的输入 <code>UIPickerView</code>。我尝试为单个选择器设置标签，但没有任何效果。我的代码如下。</p>
<pre><code>//Picker-1
pickerView1 = [ init];
pickerView1 setDataSource: self];
;
;
pickerView1.showsSelectionIndicator = YES;
;
//Picker-2
pickerView2 = [ init];
pickerView2 setDataSource: self];
;
;
pickerView2.showsSelectionIndicator = YES;
;
//Picker -1 rows
- (NSInteger)numberOfComponentsInPickerView:(UIPickerView *)pickerView{
return 1;
}
- (NSInteger)pickerView:(UIPickerView *)pickerView numberOfRowsInComponent:(NSInteger)component{
return getvalue1.count;
}
- (NSString *)pickerView:(UIPickerView *)pickerView titleForRow:(NSInteger)row forComponent:(NSInteger)component{
return ;
}
-(void)pickerView:(UIPickerView *)pickerView didSelectRow:(NSInteger)row inComponent:(NSInteger)component{
NSLog(@"You selected this: %@", );
NSArray *getvalue2 =;
}
//Picker-2 rows
-(NSInteger)numberOfComponentsInPickerView2:(UIPickerView *)pickerView{
return 1;
}
-(NSInteger)pickerView2:(UIPickerView *)pickerView numberOfRowsInComponent:(NSInteger)component{
return getvalue2.count;
}
-(NSString *)pickerView2:(UIPickerView *)pickerView titleForRow:(NSInteger)row forComponent:(NSInteger)component{
return ;
}
-(void)pickerView2:(UIPickerView *)pickerView didSelectRow:(NSInteger)row inComponent:(NSInteger)component{
NSLog(@"You selected this: %@", );
}
</code></pre>
<p>问题是在显示时都获得了第一个选择器值。选择器 2 行没有被调用。</p></p>
<br><hr><h1><strong>Best Answer-推荐答案</ strong></h1><br>
<p><p>您只能拥有一组选取器 View 委托(delegate)方法。使用每个的 <code>pickerView</code> 参数来做正确的事情:</p>
<pre><code>- (NSInteger)numberOfComponentsInPickerView:(UIPickerView *)pickerView{
return 1;
}
- (NSInteger)pickerView:(UIPickerView *)pickerView numberOfRowsInComponent:(NSInteger)component{
if (pickerView == pickerView1) {
return getvalue1.count;
} else {
return getValue2.count;
}
}
- (NSString *)pickerView:(UIPickerView *)pickerView titleForRow:(NSInteger)row forComponent:(NSInteger)component{
if (pickerView == pickerView1) {
return ;
} else {
return ;
}
}
- (void)pickerView:(UIPickerView *)pickerView didSelectRow:(NSInteger)row inComponent:(NSInteger)component{
if (pickerView == pickerView1) {
NSLog(@"You selected this: %@", );
NSArray *getvalue2 =;
} else {
NSLog(@"You selected this: %@", );
}
}
</code></pre></p>
<p style="font-size: 20px;">关于ios - 基于另一个 UIPickerView 显示 UIPickerView，我们在Stack Overflow上找到一个类似的问题：
<a href="https://stackoverflow.com/questions/32061357/" rel="noreferrer noopener nofollow" style="color: red;">
https://stackoverflow.com/questions/32061357/
</a>
</p>
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