ios - 具有大量数值的 PickerView
<p><p>我见过使用选择器 View 的示例，其中选择器的值像这样硬编码到源代码中</p>
<pre><code>- (NSString *)pickerView:(UIPickerView *)pickerView titleForRow:(NSInteger)row forComponent:(NSInteger)component {
NSString * title = nil;
switch(row) {
case 0:
title = @"a";
break;
case 1:
title = @"b";
break;
case 2:
title = @"c";
break;
}
</code></pre>
<p>但是，如果要在选择器 View 中显示 100 个数字，那将是非常不切实际的。我相信你可以在下面看到我想要做的事情。它给了我错误</p>
<pre><code>expression is not an integer constant expression
</code></pre>
<p>如何在选择器 View 中获取 0 到 100 的数字？如果有更好的方法来获取用户选择 1 到 100 之间的数字的输入，请随时发表评论。</p>
<pre><code>- (NSString *)pickerView:(UIPickerView *)pickerView titleForRow:(NSInteger)row forComponent:(NSInteger)component {
NSString * title = nil;
if (pickerView.tag == 1) // this is otherPickerview
{
otherpickerview
for (int i = 2; i < 100; i++){
switch(row) {
case i:
title = ;
break;
}
}
}
</code></pre></p>
<br><hr><h1><strong>Best Answer-推荐答案</ strong></h1><br>
<p><p>让我们试试吧:</p>
<pre><code>- (NSInteger)numberOfComponentsInPickerView:(UIPickerView *)pickerView
{
return 3;
}
- (NSInteger)pickerView:(UIPickerView *)pickerView numberOfRowsInComponent:(NSInteger)component
{
return _arr.count;
}
- (NSString *)pickerView:(UIPickerView *)pickerView titleForRow:(NSInteger)row forComponent:(NSInteger)component
{
// you can switch to other UIPickerView, and return title for row which you want.
// don't need to loop whenever titleForRow is called.
return _arr;
}
- (void)viewDidLoad
{
;
// Do any additional setup after loading the view, typically from a nib.
;
_arr = [init];
for (int i = 0; i<100; i++) {
NSString *str = ;
;
}
_pickerView.dataSource = self;
_pickerView.delegate = self;
}
</code></pre></p>
<p style="font-size: 20px;">关于ios - 具有大量数值的 PickerView，我们在Stack Overflow上找到一个类似的问题：
<a href="https://stackoverflow.com/questions/23190292/" rel="noreferrer noopener nofollow" style="color: red;">
https://stackoverflow.com/questions/23190292/
</a>
</p>
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