ios - 在我的 Apple Watch 应用程序中获取 sharedApplication' 不可用
<p><p>您好，我正在为 Apple Watch 开发一个应用程序，我的应用程序有一个按钮，我希望当单击该按钮以在配对的 iPhone 上打开 safari 时，我是 iOS 开发的新手，所以这就是我目前所拥有的:</p>
<p>InterfaceController.h</p>
<pre><code>//
//InterfaceController.h
//ToolBelt WatchKit Extension
//
//Created by Chris on 3/12/15.
//Copyright (c) 2015 Chris. All rights reserved.
//
#import <WatchKit/WatchKit.h>
#import <Foundation/Foundation.h>
@interface InterfaceController : WKInterfaceController
-(IBAction) internetbttn;
@end
@interface ViewController : UIViewController< UIWebViewDelegate >
@end
</code></pre>
<p>接口(interface) Controller .m</p>
<pre><code> #import "InterfaceController.h"
@interface InterfaceController()
@end
@implementation InterfaceController
-(IBAction) internetbttn: (id)sender {
NSURL *url = ;
[ openURL:url];
}
- (void)awakeWithContext:(id)context {
;
}
- (void)willActivate {
// This method is called when watch view controller is about to be visible to user
;
}
- (void)didDeactivate {
// This method is called when watch view controller is no longer visible
;
}
@end
</code></pre>
<p>它给我的错误是:</p>
<pre><code>ToolBelt WatchKit Extension/InterfaceController.m:22:21: 'sharedApplication' is unavailable: not available on iOS (App Extension) - Use view controller based solutions where appropriate instead.
</code></pre>
<p>如果提出这样一个菜鸟问题，任何帮助都会非常抱歉</p>
<p>提前致谢</p></p>
<br><hr><h1><strong>Best Answer-推荐答案</ strong></h1><br>
<p><p>如错误消息所示，UIApplication 类在扩展(包括 WatchKit 扩展)中不可用。无法通过 WatchKit 扩展在用户手机上打开 URL。您应该考虑采用 Handoff 来让用户快速从 Watch 应用过渡到手机应用。</p></p>
<p style="font-size: 20px;">关于ios - 在我的 Apple Watch 应用程序中获取 sharedApplication' 不可用，我们在Stack Overflow上找到一个类似的问题：
<a href="https://stackoverflow.com/questions/29024531/" rel="noreferrer noopener nofollow" style="color: red;">
https://stackoverflow.com/questions/29024531/
</a>
</p>
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