ios - 如何使用 Firebase 数据库在 Xcode/Swift 的 TableView 中显示多个路由/子节点
<p><p>这是我的 Firebase 数据库:</p>
<p> <a href="/image/6M6jO.png" rel="noreferrer noopener nofollow"><img src="/image/6M6jO.png" alt="enter image description here"/></a> </p>
<p>这是我的代码:</p>
<pre><code>class AdminSearchViewController: UIViewController, UITableViewDelegate, UITableViewDataSource {
var ref: DatabaseReference!
var jobList = ()
@IBOutlet weak var tlb2: UITableView!
func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
let cell = tableView.dequeueReusableCell(withIdentifier: "cell2", for: indexPath) as! ViewController2TableViewCell
let job: jobModel2
job = jobList
cell.ship.text = job.consignee
cell.reference.text = job.reference
return cell
}
func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
return jobList.count
}
override func viewDidLoad() {
super.viewDidLoad()
if FirebaseApp.app() == nil {
FirebaseApp.configure()
}
Database.database().reference().child("jobs").observe(DataEventType.value) { (snapshot) in
if snapshot.childrenCount>0 {
self.jobList.removeAll()
for jobs in snapshot.children.allObjects as! {
let jobObject = jobs.value as?
let jobConsignee = jobObject?["consignee"]
let jobReference = jobObject?["reference"]
let job = jobModel2( consignee: jobConsignee as! String?,
reference: jobReference as! String?
)
self.jobList.append(job)
}
self.tlb2.reloadData()
}
}
}
}
</code></pre>
<p>我面临的问题是它们在我的 TableView 中没有出现，我认为这与 .childs 有关，因为我认为我需要将其从“工作”更改为某些东西，但我想不通出去。 </p>
<p>我想显示来自所有 UID 的所有引用的列表，而不仅仅是一个。 </p>
<p>打印中显示的代码:</p>
<pre><code>func readJobs() {
let ref = Database.database().reference()
let ref1 = ref.child("jobs").queryOrderedByKey()
ref1.observeSingleEvent(of: .value, with: { snapshot in
let allUsersAndJobs = snapshot.children.allObjects as!
for user in allUsersAndJobs {
let uid = user.key
print("user id: \(uid)")
let thisUsersJobs = user.children.allObjects as!
for job in thisUsersJobs {
let jobKey = job.key
let consignee = job.childSnapshot(forPath: "consignee").value as! String
print(" job #: \(jobKey)")
print(" consignee: \(consignee)")
}
}
})
}
</code></pre></p>
<br><hr><h1><strong>Best Answer-推荐答案</ strong></h1><br>
<p><p>所以这行不通 - firebase 结构与您尝试读取的内容不匹配。</p>
<p>你的结构是</p>
<pre><code>jobs
uid_0
job_key_0
...
job_key_1
...
uid_1
job_key_0
...
</code></pre>
<p>并且您正在阅读包含直接子代的作业节点，但您不是在阅读子代的子代。</p>
<pre><code>uid_0
uid_1
etc
</code></pre>
<p>因此，Firebase 结构比您正在阅读的内容更深，因此您需要在代码中再往下阅读一层才能到达作业子节点。</p>
<p>假设 5hs... 和 7py... 是用户 ID，这里是读取每个节点的代码，打印用户 uid，然后是他们的作业</p>
<pre><code>func readJobs() {
let ref = self.ref.child("jobs")
ref.observeSingleEvent(of: .value, with: { snapshot in
let allUsersAndJobs = snapshot.children.allObjects as!
for user in allUsersAndJobs {
let uid = user.key
print("user id: \(uid)")
let thisUsersJobs = user.children.allObjects as!
for job in thisUsersJobs {
let jobKey = job.key
let consignee = job.childSnapshot(forPath: "consignee").value as! String
print(" job #: \(jobKey)")
print(" consignee: \(consignee)")
}
}
})
}
</code></pre>
<p>和输出</p>
<pre><code>user id: 5HS
job #: job_0
consignee: Anni
job #: job_1
consignee: Ralph
user id: 7py
job #: job_0
consignee: Larry
job #: job_1
consignee: Bill
</code></pre></p>
<p style="font-size: 20px;">关于ios - 如何使用 Firebase 数据库在 Xcode/Swift 的 TableView 中显示多个路由/子节点，我们在Stack Overflow上找到一个类似的问题：
<a href="https://stackoverflow.com/questions/55061509/" rel="noreferrer noopener nofollow" style="color: red;">
https://stackoverflow.com/questions/55061509/
</a>
</p>
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