ios - 过滤 Firebase 数据 Swift 3
<p><p>我正在使用 firebase 来存储将在表格 View 中显示的信息。这是数据库的截图:</p>
<p> <img src="/image/cwauC.png" alt="image"/> </p>
<p>我正在尝试仅添加来自某个“createdBy uid”的媒体:</p>
<pre><code> func fetchMyMedia() {
let ref = DatabaseReference.media.reference()
let query = ref.queryOrdered(byChild: "createdBy/uid").queryEqual(toValue: "Cdxbj1iCZUNxWRbIBllBxKqXh5P2")
query.observe(.value,
with: { snapshot in
for childSnapshot in snapshot.children {
self.myMedia.insert(childSnapshot as! Media, at: 0)
let indexPath = IndexPath(row: 0, section: 0)
}
})
}
</code></pre>
<p>“myMedia”是一个Media类型的数组</p>
<p>我收到一个错误，我无法将 FIRDataSnapshot 类型的值转换为 XXXXXX.Media。对此的任何帮助将不胜感激。</p>
<p>如果它有帮助，在不列出我的整个模型类的情况下，这就是我获取所有未过滤信息的方式......</p>
<pre><code> extension Media {
class func observeNewMedia(_ completion: @escaping (Media) -> Void) {
DatabaseReference.media.reference().observe(.childAdded, with: { snapshot in
let media = Media(dictionary: snapshot.value as! )
completion(media)
})
}
</code></pre>
<p>然后……</p>
<pre><code> func fetchMedia() {
Media.observeNewMedia { (media) in
if !self.media.contains(media) {
self.media.insert(media, at: 0)
self.tableView.reloadData()
}
}
}
</code></pre></p>
<br><hr><h1><strong>Best Answer-推荐答案</ strong></h1><br>
<p><pre><code> func fetchMyMedia() {
let ref = DatabaseReference.media.reference()
let query = ref.queryOrdered(byChild: "createdBy/uid").queryEqual(toValue: "Cdxbj1iCZUNxWRbIBllBxKqXh5P2")
query.observe(.childAdded, with: { snapshot in
let media = Media(dictionary: snapshot.value as! )
self.myMedia.insert(media, at: 0)
self.tableView.reloadData()
</code></pre></p>
<p style="font-size: 20px;">关于ios - 过滤 Firebase 数据 Swift 3，我们在Stack Overflow上找到一个类似的问题：
<a href="https://stackoverflow.com/questions/44556781/" rel="noreferrer noopener nofollow" style="color: red;">
https://stackoverflow.com/questions/44556781/
</a>
</p>
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