ios - iOS 上的 Firebase 离线功能
<p><p>我使用 Firebase 离线功能，特别是我使用它来确定用户上次在线或在线的时间。在测试的过程中，遇到了这样一个问题，如果我注销了，Disconnect功能不起作用，虽然我没有取消Disconnect功能。我明白在注销之前，我可以自己发送这个数据，但是这个功能的意义会从盒子里消失。告诉我如何解决这个问题？</p>
<p>这个函数决定了用户的事件，我在<code>MainTabBarController</code>中调用它(它被用作根 Controller )</p>
<pre><code>func setupLastSeenActivity() {
DispatchQueue.main.async {
let realmManager = RealmManager()
guard let currentUserID = realmManager.getCurrentUser()?.id else { return }
DispatchQueue.global(qos: .background).async {
let ref = Database.database().reference().child(MainGateways.users.rawValue).child(currentUserID)
let userSearchLocationRef = Database.database().reference().child(UserSearchLocationKeys.userSearchLocationModel.rawValue).child(currentUserID)
let parameters =
ref.updateChildValues(parameters, withCompletionBlock: { (error, ref) in
})
userSearchLocationRef.updateChildValues(parameters, withCompletionBlock: { (error, ref) in
})
let disconnectParameters = as
ref.onDisconnectUpdateChildValues(disconnectParameters, withCompletionBlock: { (error, ref) in
guard let _error = error else { return }
debugPrint(_error.localizedDescription)
})
userSearchLocationRef.onDisconnectUpdateChildValues(disconnectParameters, withCompletionBlock: { (error, ref) in
guard let _error = error else { return }
debugPrint(_error.localizedDescription)
})
}
}
}
</code></pre>
<p><code>FirebaseAuthManager</code></p> 的注销功能
<pre><code>func logOut(completion: (() -> Void)?) {
DispatchQueue.main.async {
do {
let pushNotificationManager = PushNotificationManager()
pushNotificationManager.unregisterPushNotification()
pushNotificationManager.removeTokenWhenLogOut(success: nil)
// Observers
FIRFriendsDatabaseManager.shared.observeNewFriend(false, success: nil, fail: nil)
FIRFriendsDatabaseManager.shared.observeFriendRemoved(false, success: nil, fail: nil)
let firChatCardManager = FIRChatCardManager()
firChatCardManager.syncChatCardModels(false)
FacebookManager.logOut()
Database.database().reference().removeAllObservers()
let firebaseGeneralDatabaseManager = FirebaseDatabaseGeneralManager()
firebaseGeneralDatabaseManager.logOut()
try Auth.auth().signOut()
let realmManager = RealmManager()
realmManager.logOut()
let appManager = AppManager()
appManager.logOut(isDeleteAccount: false, completion: completion)
} catch {
debugPrint(error.localizedDescription)
}
}
}
</code></pre></p>
<br><hr><h1><strong>Best Answer-推荐答案</ strong></h1><br>
<p><p>我做了一个统计连接设备数量的云函数，如果连接设备数量为0，那么我设置值isOnline = false 并设置lastSeenTimeStamp</p>
<pre><code>const functions = require('firebase-functions');
const admin = require('firebase-admin');
module.exports = functions.database.ref('userOnlineDevices/{userID}/{onlineSystemModelID}')
.onWrite(event => {
const snapshot = event.data;
const userID = event.params.userID;
const onlineSystemModelID = event.params.onlineSystemModelID;
const currentData = event.data.current;
const previousData = event.data.previous;
console.log("currentData.val()", currentData.val(), "previousData.val()", previousData.val());
if (currentData.val() && !previousData.val()) {
// value created
const checkUserRef = admin.database().ref("users").child(userID);
const checkUserRefPromise = checkUserRef.once("value", function(checkUserRefSnap, error) {
if (error) {
return console.log("created checkUserRefPromise error", error);
}
if (checkUserRefSnap.val()) {
const checkUserID = checkUserRefSnap.val()["id"];
if (checkUserID == null) {
return console.log("checkUserID == null")
} else {
console.log("checkUserID", checkUserID)
}
const recentActivityTimeStamp = Math.floor(Date.now() / 1000);
const userRef = admin.database().ref("users").child(userID);
const userRefPromise = userRef.update({
"isOnline": true
});
const userSearchLocationModelRef = admin.database().ref("userSearchLocationModel").child(userID);
const userSearchLocationModelRefPromise = userSearchLocationModelRef.update({
"isOnline": true,
"recentActivityTimeStamp": recentActivityTimeStamp
});
return Promise.all();
} else {
return console.log("checkUserRefSnap.val() == null")
}
});
return Promise.all();
} else if (!currentData.val() && previousData.val()) {
// value removed
const checkUserRef = admin.database().ref("users").child(userID);
const checkUserRefPromise = checkUserRef.once("value", function(checkUserRefSnap, error) {
if (error) {
return console.log(error);
}
if (checkUserRefSnap.val()) {
const checkUserID = checkUserRefSnap.val()["id"];
if (checkUserID == null) {
return console.log("checkUserID == null")
} else {
console.log("checkUserID", checkUserID)
}
if (userID) {
const removedTimeStamp = new Date() / 1000;
const userRef = admin.database().ref("users").child(userID);
const userRefPromise = userRef.update({
"isOnline": false,
"lastSeenTimeStamp": removedTimeStamp
});
const userSearchLocationModelRef = admin.database().ref("userSearchLocationModel").child(userID);
const userSearchLocationModelRefPromise = userSearchLocationModelRef.update({
"isOnline": false,
"lastSeenTimeStamp": removedTimeStamp
});
return Promise.all();
} else {
return console.log("removed, userID == null");
}
} else {
return console.log("removed, checkUserRefSnap.val() == null");
}
});
return Promise.all();
} else {
// updated
const checkUserRef = admin.database().ref("users").child(userID);
const checkUserRefPromise = checkUserRef.once("value", function(checkUserRefSnap, error) {
if (error) {
return console.log(error);
}
if (checkUserRefSnap.val()) {
const checkUserID = checkUserRefSnap.val()["id"];
if (checkUserID == null) {
return console.log("checkUserID == null")
} else {
console.log("checkUserID", checkUserID)
}
const recentActivityTimeStamp = Math.floor(Date.now() / 1000);
const userRef = admin.database().ref("users").child(userID);
const userRefPromise = userRef.update({
"isOnline": true
});
const userSearchLocationModelRef = admin.database().ref("userSearchLocationModel").child(userID);
const userSearchLocationModelRefPromise = userSearchLocationModelRef.update({
"isOnline": true,
"recentActivityTimeStamp": recentActivityTimeStamp
});
return Promise.all();
} else {
return console.log("updated checkUserRefSnap.val() == null");
}
});
return Promise.all();
}
});
</code></pre></p>
<p style="font-size: 20px;">关于ios - iOS 上的 Firebase 离线功能，我们在Stack Overflow上找到一个类似的问题：
<a href="https://stackoverflow.com/questions/44472968/" rel="noreferrer noopener nofollow" style="color: red;">
https://stackoverflow.com/questions/44472968/
</a>
</p>
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