ios - RxSwift 订阅数据模型属性更改的正确方法
<p><p>这里是 RxSwift 的新手。我有一个(MVVM) View 模型，它代表一个类似新闻源的页面，订阅数据模型属性更改的正确方法是什么？在以下示例中，<code>startUpdate()</code> 不断更新 <code>post</code>。计算的属性 <code>messageToDisplay</code> 和 <code>shouldShowHeart</code> 驱动一些 UI 事件。 </p>
<pre><code>struct Post {
var iLiked: Bool
var likes: Int
...
}
class PostViewModel: NSObject {
private var post: Post
var messageToDisplay: String {
if post.iLiked { return ... }
else { return .... }
}
var shouldShowHeart: Bool {
return iLiked && likes > 10
}
func startUpdate() {
// network request and update post
}
...
}
</code></pre>
<p>在我看来，为了使整个事情具有反应性，我必须将 <code>Post</code> 的每个属性和所有计算属性都转换为 <code>Variable</code>？我觉得不太对劲。</p></p>
<br><hr><h1><strong>Best Answer-推荐答案</ strong></h1><br>
<p><p>//类 NetworkRequest 或任何名称</p>
<pre><code>static func request(endpoint: String, query: = [:]) -> Observable<> {
do {
guard let url = URL(string: API)?.appendingPathComponent(endpoint) else {
throw EOError.invalidURL(endpoint)
}
return manager.rx.responseJSON(.get, url)
.map({ (response, json) -> in
guard let result = json as? else {
throw EOError.invalidJSON(url.absoluteString)
}
return result
})
} catch {
return Observable.empty()
}
}
static var posts: Observable<> = {
return NetworkRequest.request(endpoint: postEndpoint)
.map { data in
let posts = data["post"] as? [] ?? []
return posts
.flatMap(Post.init)
.sorted { $0.name < $1.name }
}
.shareReplay(1)
}()
class PostViewModel: NSObject {
let posts = Variable<>([])
let disposeBag = DisposeBag()
override func viewDidLoad() {
super.viewDidLoad()
posts
.asObservable()
.subscribe(onNext: { _ in
DispatchQueue.main.async {
//self?.tableView?.reloadData() if you want to reload all tableview
self.tableView.insertRows(at: , with: UITableViewRowAnimation.none) // OR if you want to insert one or multiple rows.
//OR update UI
}
})
.disposed(by: disposeBag)
posts.asObservable()
.bind(to: tableView.rx.items) { (tableView: UITableView, index: Int, element: Posts) in
let cell = tableView.dequeueReusableCell(withIdentifier: "postCell") as! PostCell
//for example you need to update the view model and cell with textfield.. if you want to update the ui with a cell then use cell.button.tap{}. hope it works for you.
cell.textField.rx.text
.orEmpty.asObservable()
.bind(to: self.posts.value.name!)
.disposed(by: cell.disposeBag)
return cell
}
startDownload()
}
}
func startDownload {
posts.value = NetworkRequest.posts
}
</code></pre>
<p>如果您想更改任何内容，请使用 subscribe、bind、concat .. 您可以使用许多方法和属性。</p></p>
<p style="font-size: 20px;">关于ios - RxSwift 订阅数据模型属性更改的正确方法，我们在Stack Overflow上找到一个类似的问题：
<a href="https://stackoverflow.com/questions/49212915/" rel="noreferrer noopener nofollow" style="color: red;">
https://stackoverflow.com/questions/49212915/
</a>
</p>
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