ios - 从 UIpickerview 中提取值作为变量
<p><p>所以我有这个 UIpickerview 的代码,我想获得选择作为变量的值以供以后使用,我尝试使用可变重力但它说“从未使用过可变重力的初始化......”这是我的代码:</p>
<pre><code> var g = ["9.807", "3.711"]
func numberOfComponents(in pickerView: UIPickerView) -> Int {
return 1
}
func pickerView(_ pickerView: UIPickerView, numberOfRowsInComponent component: Int) -> Int {
return g.count
}
func pickerView(_ pickerView: UIPickerView, titleForRow row: Int, forComponent component: Int) -> String? {
return g
}
func pickerView(_ pickerView: UIPickerView, didSelectRow row: Int, inComponent component: Int) {
var gravity = Float(g)
}
</code></pre></p>
<br><hr><h1><strong>Best Answer-推荐答案</ strong></h1><br>
<p><p>您需要在方法范围之外声明 var:</p>
<pre><code>var gravity: Float?
func pickerView(_ pickerView: UIPickerView, didSelectRow row: Int, inComponent component: Int) {
gravity = Float(g)
}
</code></pre>
<p>局部变量的作用域仅限于方法,当您不在方法中使用它时,您会收到警告。</p>
<p>这是 Swift 而不是 Javascript :)</p></p>
<p style="font-size: 20px;">关于ios - 从 UIpickerview 中提取值作为变量,我们在Stack Overflow上找到一个类似的问题:
<a href="https://stackoverflow.com/questions/43235727/" rel="noreferrer noopener nofollow" style="color: red;">
https://stackoverflow.com/questions/43235727/
</a>
</p>
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