ios - Swift 如何更新(修改、删除、添加)JSON 条目
<p><p>您好，我需要一些帮助，我正在制作一个 IOS 应用程序，它从 JSON API 获取数据，然后在表格上显示结果，当我点击表格中的结果时，它会转到第二个 ViewController 我正在展示细节。我想要做的是更新我在详细信息中显示的信息，通过从表本身中删除它们来从 JSON 中删除条目，并添加一个要保存在 JSON 上的新条目。</p>
<p>这是 JSON 结构:</p>
<pre><code> {
_id: "57eec6c9dfc2fb03005c0dd0",
ssid: "nonummy",
password: "accumsan",
lat: 29.39293,
lon: 115.71771,
summary: "curae nulla dapibus dolor vel est donec odio justo sollicitudin ut",
__v: 0,
likes: 1,
unlikes: 0,
bssid: "EF:CD:AB:56:34:12"
},
</code></pre>
<p>我希望能够更新 SSID、密码和摘要。</p>
<p>这是我用来从 JSON 中获取结果的代码，并且运行良好</p>
<p>代码:</p>
<pre><code> let url = URL(string:"https://fierce-peak-97303.herokuapp.com/api/wifi")!
let task = URLSession.shared.dataTask(with: url) { (data, response, error) in
if error != nil {
print(error)
}else {
if let urlContent = data {
do {
let jsonResult = try JSONSerialization.jsonObject(with: urlContent, options: JSONSerialization.ReadingOptions.mutableContainers)
//print(jsonResult))
for item in(jsonResult as? NSArray)! {
let ssid = (item as? NSDictionary)?["ssid"] as? NSString
//print(ssid)
}
self.tableData = jsonResult as! NSArray
DispatchQueue.main.sync(execute: {
self.table.reloadData()
})
}catch {
print("No Json Result Was Found")
}
}
}
}
task.resume()
</code></pre>
<p>例如，如果我单击表格的一行，我希望能够更新密码。</p></p>
<br><hr><h1><strong>Best Answer-推荐答案</ strong></h1><br>
<p><p>我设法做到了:所有格式都为 swift 3</p>
<pre><code> //declare parameter as a dictionary which contains string as key andvalue combination.
let parameters = ["ssid": newSSID.text!,"password": newPass.text!,"lat": newLat.text!,"lon": newLon.text!,"summary": newSum.text!] as Dictionary<String, String>
//create the url with NSURL
let url = URL(string: "https://fierce-peak-97303.herokuapp.com/api/wifi")
//create the session object
let session = URLSession.shared
//now create the NSMutableRequest object using the url object
let request = NSMutableURLRequest(url: url!)
request.httpMethod = "POST"
var err : NSError?
do {
request.httpBody = try JSONSerialization.data(withJSONObject: parameters, options: [])
}catch{
print("error")
}
request.addValue("application/json", forHTTPHeaderField: "Content-Type")
request.addValue("application/json", forHTTPHeaderField: "Accept")
//create dataTask using the session object to send data to the server
let task = session.dataTask(with: request as URLRequest, completionHandler: {data, response, error -> Void in
print("Response: \(response)")
let strData = NSString(data: data!, encoding: String.Encoding.utf8.rawValue)
print("Body: \(strData)")
var err: NSError?
do {
var json = try JSONSerialization.jsonObject(with: data!, options: .mutableLeaves) as? NSDictionary
}catch{
print("JSON error")
}
// Did the JSONObjectWithData constructor return an error? If so, log the error to the console
if(err != nil) {
print(err!.localizedDescription)
let jsonStr = NSString(data: data!, encoding: String.Encoding.utf8.rawValue)
print("Error could not parse JSON: '\(jsonStr)'")
}
else {
// The JSONObjectWithData constructor didn't return an error. But, we should still
// check and make sure that json has a value using optional binding.
do {
let json = try JSONSerialization.jsonObject(with: data!, options: .mutableLeaves) as? NSDictionary
if let parseJSON = json {
// Okay, the parsedJSON is here, let's get the value for 'success' out of it
let success = parseJSON["success"] as? Int
print("Success: \(success)")
}
else {
// Woa, okay the json object was nil, something went worng. Maybe the server isn't running?
let jsonStr = NSString(data: data!, encoding: String.Encoding.utf8.rawValue)
print("Error could not parse JSON: \(jsonStr)")
}
}catch{
print("JSON error")
}
}
</code></pre></p>
<p style="font-size: 20px;">关于ios - Swift 如何更新(修改、删除、添加)JSON 条目，我们在Stack Overflow上找到一个类似的问题：
<a href="https://stackoverflow.com/questions/40094922/" rel="noreferrer noopener nofollow" style="color: red;">
https://stackoverflow.com/questions/40094922/
</a>
</p>
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